In a Wheatstone network, the resistances in cyclic order are $P=10 \Omega, Q=5 \Omega, S=4 \Omega$ and $R$ $=4 \Omega$ Then, for the bridge to balance,
- A$5 \Omega$ should be connected in parallel to $Q=5 \Omega$
- B$10 \Omega$ should be connected in series with $Q=5 \Omega$
- C$5 \Omega$ should be connected in series with $P=10 \Omega$
- ✓$10 \Omega$ should be connected in parallel to $P=10 \Omega$
Answer: D.
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