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14 questions · self-marked practice — reveal the answer and mark yourself.

Question 12 Marks
$a, b, c, d$ are positive numbers and $\frac{a}{b}=\frac{c}{d}$ is given.$\quad \frac{a}{b}=\frac{ rc }{ rd }$


Answer
True
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Question 22 Marks
$a, b, c, d$ are positive numbers and $\frac{a}{b}=\frac{c}{d}$ is given.$\quad \frac{c}{d}=\frac{c-a}{d-b}$
Answer
False Here, different numbers a and b are subtracted from numerator and denominator.
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Question 32 Marks
$a, b, c, d$ are positive numbers and $\frac{a}{b}=\frac{c}{d}$ is given.$\frac{a}{b}=\frac{a c}{b d}$
Answer
False Here, numerator and denominator are multiplied by two different numbers a and b.
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Question 42 Marks
$a, b, c, d$ are positive numbers and $\frac{a}{b}=\frac{c}{d}$ is given.$\quad \frac{a}{c}=\frac{b}{d}$
Answer
True
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Question 52 Marks
$a, b, c, d$ are positive numbers and $\frac{a}{b}=\frac{c}{d}$ is given. $\quad \frac{a+b}{b}=\frac{c+d}{d}$
Answer
True
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Question 62 Marks
Compare the following : $\quad \frac{9.2}{5.1}, \frac{3.4}{7.1}$
Answer
$\begin{array}{ll}\quad & \frac{9.2}{5.1}, \frac{3.4}{7.1} \\ & 9.2 \times 7.1=65.32 \\ & 5.1 \times 3.4=17.34 \\ & \text { Here, } 65.32>17.34 \\ \therefore \quad & \frac{9.2}{5.1}>\frac{3.4}{7.1}\end{array}$
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Question 72 Marks
Compare the following : $\frac{\sqrt{80}}{\sqrt{48}}, \frac{\sqrt{45}}{\sqrt{27}}$
Answer
$\begin{array}{ll}
& \frac{\sqrt{80}}{\sqrt{48}}, \frac{\sqrt{45}}{\sqrt{27}} \\
& \sqrt{80} \times \sqrt{27}=\sqrt{2160} \\
& \sqrt{48} \times \sqrt{45}=\sqrt{2160} \\
& \text { Here, } 2160=2160 \\
\therefore \quad & \sqrt{2160}=\sqrt{2160} \\
\therefore \quad & \frac{\sqrt{80}}{\sqrt{48}}=\frac{\sqrt{45}}{\sqrt{27}}
\end{array}$
Alternate method:
$\frac{\sqrt{80}}{\sqrt{48}}, \frac{\sqrt{45}}{\sqrt{27}}$
Consider, $\frac{\sqrt{80}}{\sqrt{48}}=\frac{\sqrt{16 \times 5}}{\sqrt{16 \times 3}}=\frac{4 \sqrt{5}}{4 \sqrt{3}}=\frac{\sqrt{5}}{\sqrt{3}}$
$\frac{\sqrt{45}}{\sqrt{27}}=\frac{\sqrt{9 \times 5}}{\sqrt{9 \times 3}}=\frac{3 \sqrt{5}}{3 \sqrt{3}}=\frac{\sqrt{5}}{\sqrt{3}}$
Here, $\frac{\sqrt{5}}{\sqrt{3}}=\frac{\sqrt{5}}{\sqrt{3}}$
$\therefore \quad \frac{\sqrt{80}}{\sqrt{48}}=\frac{\sqrt{45}}{\sqrt{27}}$
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Question 82 Marks
Compare the following : $\frac{5}{18}, \frac{17}{121}$
Answer
$\begin{array}{ll}\quad & \frac{5}{18}, \frac{17}{121} \\ & 5 \times 121=605 \\ & 18 \times 17=306 \\ & \text { Here, } 605>306 \\ \therefore \quad & \frac{5}{18}>\frac{17}{121}\end{array}$
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Question 92 Marks
Compare the following : $\frac{3 \sqrt{5}}{5 \sqrt{7}}, \frac{\sqrt{63}}{\sqrt{125}}$
Answer
$\begin{aligned}
\frac{3 \sqrt{5}}{5 \sqrt{7}}, \frac{\sqrt{63}}{\sqrt{125}} & \\
3 \sqrt{5} \times \sqrt{125} & =3 \times \sqrt{5 \times 125} \\
& =3 \times \sqrt{5 \times 25 \times 5} \\
& =3 \times 5 \times 5 \\
& =3 \times 25=75 \\
5 \sqrt{7} \times \sqrt{63} & =5 \times \sqrt{7 \times 63} \\
& =5 \times \sqrt{7 \times 9 \times 7} \\
& =5 \times 3 \times 7=105
\end{aligned}$
Here, $75<105$
$\therefore \quad \frac{3 \sqrt{5}}{5 \sqrt{7}}<\frac{\sqrt{63}}{\sqrt{125}}$
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Question 102 Marks
Compare the following : $\quad \frac{\sqrt{5}}{3}, \frac{3}{\sqrt{7}}$
Answer
$\begin{array}{ll}\quad & \frac{\sqrt{5}}{3}, \frac{3}{\sqrt{7}} \\ & \sqrt{5} \times \sqrt{7}=\sqrt{35} \\ & 3 \times 3=9=\sqrt{9^2}=\sqrt{81} \\ & \text { Here, } 35<81 \\ \therefore \quad & \sqrt{35}<\sqrt{81} \\ \therefore \quad & \frac{\sqrt{5}}{3}<\frac{3}{\sqrt{7}}\end{array}$
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Question 112 Marks
Find the following ratios :
The lengths of sides of a rectangle are 5 cm and 3.5 cm. Find the ratio of numbers denoting its perimeter to area.
Answer
Length of rectangle $=( l )=5 cm$,
Breadth of rectangle $=(b)=3.5 cm$
Perimeter of the rectangle $=2(l+b)$
$=2(5+3.5)$
$=2 \times 8.5$
$=17 cm$
Area of the rectangle $= Ixb$
$=5 \times 3.5$
$=17.5 cm^2$
Ratio of numbers denoting perimeter to the area of rectangle
$\begin{aligned}
& =\frac{\text { perimeter }}{\text { area }} \\
& =\frac{17}{17.5} \\
& =\frac{17 \times 10}{17.5 \times 10} \\
& =\frac{170}{175} \\
& =\frac{5 \times 34}{5 \times 35} \\
& =\frac{34}{35} \\
& =34: 35
\end{aligned}$
$\therefore$ Ratio of numbers denoting perimeter to the area of rectangle is $34: 35$.
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Question 122 Marks
Find the following ratios : The ratio of diagonal of a square to its side, if the length of side is 7 cm.
Answer
Length of side of square = 7 cm
$\therefore$ Diagonal of square $= \sqrt{2} \times$ side
$= \sqrt{2} \times 7$
$= 7 \sqrt{2} cm$
Ratio of diagonal of a square to its side
$=\frac{\text { diagonal }}{\text { side }}$
$=\frac{7 \sqrt{2}}{7}$
$=\frac{\sqrt{2}}{1}$
$=\sqrt{2}: 1$
$\therefore$ The ratio of diagonal of a square to its side is $\sqrt{2} : 1$.
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Question 132 Marks
Find the following ratios $:$ The ratio of circumference of circle with radius $r$ to its area.
Answer
Let the radius of the circle is $r.$
$\therefore$ circumference $= 2\pi r$ and area $= \pi r^2$
Ratio of circumference to the area of circle
$=\frac{\text { circumference }}{\text { area }}$
$=\frac{2 \pi r }{\pi r ^2}$
$=\frac{2}{ r }$
$=2: r$
$\therefore$ The ratio of circumference of circle with radius $r$ to its area is $2: r$.
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Question 142 Marks
Find the following ratios $:$ The ratio of radius to circumference of the circle.
Answer
Let the radius of circle be $r.$
then, its circumference $= 2\pi r$
Ratio of radius to circumference of the circle
$=\frac{\text { radius }}{\text { circumference }}$
$=\frac{ r }{2 \pi r }$
$=\frac{1}{2 \pi}$
$=1: 2 \pi$
The ratio of radius to circumference of the circle is $1: 2 \pi$.
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