Question 11 Mark
Write IUPAC names of the following compound:$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{CH}-\text{CH}-\text{C}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\ \ \ \ \text{OH}\ \ \ \ \text{CH}_3$
Answer2, 2, 4-Trimethyl pentan-3-ol.
View full question & answer→Question 21 Mark
Explain why is ortho nitrophenol more acidic than ortho methoxyphenol?
Answer
The nitro-group is an electron-withdrawing group. The presence of this group in the ortho position decreases the electron density in the O-H bond. As a result, it is easier to lose a proton. Also, the o-nitrophenoxide ion formed after the loss of protons is stabilized by resonance. Hence, ortho nitrophenol is a stronger acid. On the other hand, methoxy group is an electron-releasing group. Thus, it increases the electron density in the O-H bond and hence, the proton cannot be given out easily. For this reason, ortho-nitrophenol is more acidic than ortho-methoxyphenol.
View full question & answer→Question 31 Mark
Give equation of the following reaction:Treating phenol wih chloroform in presence of aqueous NaOH.
Question 41 Mark
When phenol is treated with bromine water, white precipitate is obtained. Give the structure and the name of the compound formed.
Answer
When phenol is treated with bromine water, 2,4,6-tribromophenol is formed as white precipitate.
View full question & answer→Question 51 Mark
Name the following compounds according to IUPAC system.
Question 61 Mark
Write IUPAC names of the following compound:$\text{HO}-\text{CH}_2-\text{CH}-\text{CH}_2-\text{OH}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$
View full question & answer→Question 71 Mark
Write IUPAC names of the following compound:$\text{H}_3\text{C}-\text{CH}-\text{CH}_2-\text{CH}-\text{CH}-\text{CH}_2-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\ \ \ \ \ \text{C}_2\text{H}_5$
Answer5-Ethyl heptanes-2, 4-diol.
View full question & answer→Question 81 Mark
Alcohols react with active metals e.g. Na, K etc. to give corresponding alkoxides. Write down the decreasing order of reactivity of sodium metal towards primary, secondary and tertiary alcohols.
Answer
Decreasing order of reactivity of sodium metal is: 1° > 2° > 3°
Alcohols react with sodium metal to form alkoxides and hydrogen is liberated:
$\text{R}-\text{O}-\text{H}+\text{Na}\rightarrow\text{RO}-\text{Na}^{+}+\frac{1}{2}\text{H}_2$
The order of reactivity of alcohols is primary > secondary > tertiary. This can be explained on the basis of cleavage of O – H bond. The alkyl groups are electron releasing groups (+1 effect) and they increase the electron density around the oxygen. As a result, the electrons of O – H bond cannot be withdrawn strongly towards oxygen and O – H remains strong. Therefore, greater is the number, of alkyl groups present, smaller will be reactivity of alcohol.
View full question & answer→Question 91 Mark
Suggest a reagent for the following conversion.
AnswerPyridinium cholochromate (PCC), a complex of chromium trioxide with pyridine and HCl
$CH_3-CH-CH-CH_2OH$
$PCC\ CH_3-CH-CH-CHO.$
View full question & answer→Question 101 Mark
Give reason for the higher boiling point of ethanol in comparison to methoxymethane.
AnswerEthanol undergoes intermolecular H-bonding due to the presence of a hydrogen atom attached to the electronegative oxygen atom. As a result, ethanol exists as associated molecules.
Consequently, a large amount of energy is required to break these hydrogen bonds. Therefore, the boiling point of ethanol is higher than that of methoxymethane which does not form H-bonds.
View full question & answer→Question 111 Mark
Write structures of the products of the following reactions:$\text{CH}_3-\text{CH}=\text{CH}_2\ \xrightarrow{\text{H}_2 \text{O}/\text{H}^+}$
Answer$\text{CH}_3-\text{CH}-\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$Propane-2-ol
View full question & answer→Question 121 Mark
Give IUPAC name of the following ether:$\text{CH}_3\text{CH}_2\text{CH}_2\text{OCH}_3$
View full question & answer→Question 131 Mark
Give IUPAC name of the following ether:$\text{O}_2\text{N}-\text{C}_6\text{H}_4-\text{OCH}_3(\rho)$
View full question & answer→MCQ 141 Mark
Which of the following is most soluble in water?
- A
$n-$ butyl alcohol
- B
Iso$-$butyl alcohol
- ✓
- D
AnswerAmongst isomeric alcohols, the solubility increases with branching. This is due to the reason that as the branching increases, the surface area of the non-polar hydrocarbon and the solubility increases.
So, the sequence of solubility of alcohols are
Tertiary alcohol $>$ secondary alcohol $>$ primary alcohol
View full question & answer→Question 151 Mark
Write structure of the compound whose IUPAC names are as follow:2-Methylbutan-2-ol.
Answer$\ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{C}-\text{CH}_2-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$
View full question & answer→Question 161 Mark
Complete the reaction equation:
Question 171 Mark
Out of o-nitrophenol and o-cresol which is more acidic?
AnswerNitro group is electron is electron withdrawing while $-CH_3$ group is electron releasing.
As a result, O – H bond in o-nitrophenol is much weaker than the O – H bond in o-cresol and hence o-nitrophenol is much more acidic than o-cresol. View full question & answer→Question 181 Mark
Name the reagent used in the following reaction:Oxidation of a primary alcohol to aldehyde.
AnswerPyridinium chlorochromate (PCC), $(\text{C}_5\text{H}_5\text{NH})+\text{ClCrO}_3\ ^-$ in $\text{CH}_2\text{Cl}_2$or Pyridinium dichromate (PDC), $[(\text{C}_5\text{H}_5\text{NH})_2]^{2+}\text{Cr}_2\text{O}_{7^{2-}} $ in $\text{CH}_2\text{Cl}_2$
View full question & answer→Question 191 Mark
Show how will you synthesise:pentan-1-ol using a suitable alkyl halide?
AnswerWhen 1-chloropentane is treated with NaOH, pentan-1-ol is produced.$\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{Cl}+\text{NaOH}\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{OH}+\text{NaCl}\\ \text{1-Chloropentane} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Pantan-1-ol}$
View full question & answer→Question 201 Mark
Show how are the following alcohols prepared by the reaction of a suitable Grignard reagent on methanal?
Question 211 Mark
Name the following compounds according to IUPAC system.$\text{H}_2\text{C}=\text{CH}-\text{CH}-\text{CH}_2-\text{CH}_2-\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$
View full question & answer→Question 221 Mark
Explain the following with an example.Williamson ether synthesis.
Answer
Williamson ether synthesis:
Williamson ether synthesis is a laboratory method to prepare symmetrical and unsymmetrical ethers by allowing alkyl halides to react with sodium alkoxides.
This reaction involves $SN_2$ attack of the alkoxide ion on the alkyl halide. Better results are obtained in case of primary alkyl halides.
If the alkyl halide is secondary or tertiary, then elimination competes over substitution. View full question & answer→Question 231 Mark
Give the major products that are formed by heating the following ethers with HI.
$ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{|}\\\text{CH}_3-\text{CH}_2-\text{CH}-\text{CH}_2-\text{O}-\text{CH}_2-\text{CH}_3$
Answer$\text{CH}_3-\text{CH}_2-\text{CH}-\text{CH}_2\text{OH}+\text{CH}_3\text{CH}_2\text{I} \ \ \ \ \ \ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{|}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
View full question & answer→Question 241 Mark
Name the following compounds according to IUPAC system.$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_2\text{OH}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{CH}-\text{CH}_2-\text{CH}-\text{CH}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$
Answer2, 5-Dimethylhexane-1, 3-diol.
View full question & answer→Question 251 Mark
Explain why sodium metal can be used for drying diethyl ether but not ethyl alcohol.
AnswerDue to presence of an active hydrogen atom, ethyl alcohol reacts with sodium metal.
$2\text{CH}_3-\text{CH}_2-\text{OH}+2\text{Na}\rightarrow2\text{CH}_3-\text{CH}_2-\text{ONa}+\text{H}_2$
Diethyl ether, on the other hand, does not have replaceable hydrogen atom therefore does not react with sodium metal hence can be dried by metallic sodium.
View full question & answer→Question 261 Mark
What is the order of dehydration of primary, secondary and tertiary alcohols?
AnswerTertiary alcohols > Secondary alcohols > Primary alcohols.
View full question & answer→Question 271 Mark
Write structures of the products of the following reactions:$\text{CH}_3-\text{CH}_2-\text{CH}-\text{CHO}\xrightarrow{\text{NaBH}_4}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Answer$\text{CH}_3-\text{CH}_2-\text{CH}-\text{CH}_2\text{OH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
View full question & answer→Question 281 Mark
Show how will you synthesise:cyclohexylmethanol using an alkyl halide by an $S_N2$ reaction.
Answer
When chloromethylcyclohexane is treated with sodium hydroxide, cyclohexylmethanol is obtained.
View full question & answer→Question 291 Mark
Write the names of reagents and equations for the preparation of the following ethers by Williamson’s synthesis:Ethoxybenzene.
Question 301 Mark
How are the following conversions carried out?Ethyl magnesium chloride → Propan-1-ol.
Answer
When ethyl magnesium chloride is treated with methanal, an adduct is the produced which gives propan-1-ol on hydrolysis.
View full question & answer→Question 311 Mark
What is absolute alcohol?
Answer100% ethyl alcohol is called absolute alcohol.
View full question & answer→Question 321 Mark
Give equation of the following reaction:Bromine in $CS_2$ with phenol.
View full question & answer→Question 331 Mark
How are the following conversions carried out?Propene → Propan-2-ol.
AnswerIf propene is allowed to react with water in the presence of an acid as a catalyst, then propan-2-ol is obtained.
$\text{CH}_3-\text{CH}=\text{CH}_2+\text{H}_2\text{O}\stackrel{{\text{H}^{+}}}{{\rightleftharpoons}}\text{CH}_3-\text{CH}-\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\\ \text{Propene}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Propan-2-ol}$
View full question & answer→Question 341 Mark
Write the IUPAC name of the following compounds.
- $\text{CH}_3-\text{CH}-\text{CH}-\text{CH}-\text{CH}-\text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \ \ \ \ \ \ \ \ \ \ {|} \ \ \ \ \ \ \ \ \ \ {|} \ \ \ \ \ \ \ \ \ \ {|} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \ \ \ \ \text{OH} \ \ \ \ \ \text{C}_2\text{H}_5 \ \ \text{OH}$
-
Answer
- 3-Ethyl-5-methylhexan-2,4-diol.
- 1-Methoxy-3-3nitrocyclohexan.
View full question & answer→Question 351 Mark
Write the equation of the reaction of hydrogen iodide with:1-propoxypropane.
Answer$\text{CH}_3\text{CH}_2\text{CH}_2\text{OCH}_2\text{CH}_2\text{CH}_3\xrightarrow[373\text{K}]{\text{HI}}\text{CH}_3\text{CH}_2\text{CH}_2-\text{OH}+\text{CH}_3\text{CH}_2\text{CH}_2\text{I}\\\ \ \ \ \ \ \ \ \text{1-Propoxypropane}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Propan-1-ol}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Iodopropane}$
View full question & answer→Question 361 Mark
Name the following compounds according to IUPAC system.$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_2\text{OH}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{CH}_2-\text{CH}-\text{CH}-\text{CH}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_2\text{Cl}\ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Answer3-Chloromethyl-2-isopropylpentan-1-ol.
View full question & answer→Question 371 Mark
Give IUPAC name of the following ether:$\text{CH}_3\text{OCH}_2\text{CH}_2\text{Cl}$
Answer2-Chlorlo-l-methoxyethane.
View full question & answer→Question 381 Mark
What is the structure and IUPAC name of glycerol?
Answer$\text{CH}_2\text{OH} \\ \ | \\ \text{CHOH} \\ \ | \\ \text{CH}_2\text{OH}$
IUPAC name of glycerol is Propane-1,2,3-triol.
View full question & answer→Question 391 Mark
You are given benzene, conc. $H_2SO_4$ and NaOH. Write the equations for the preparation of phenol using these reagents.
View full question & answer→Question 401 Mark
How are the following conversions carried out?Benzyl chloride → Benzyl alcohol.
Answer
If benzyl chloride is treated with NaOH (followed by acidification) then benzyl alcohol is produced.
View full question & answer→Question 411 Mark
Predict the products of the following reactions:$\text{CH}_3-\text{CH}_2-\text{CH}_2-\text{O}-\text{CH}_3+\text{HBr}\xrightarrow{\ \ \ }$
Answer$\text{CH}_3-\text{CH}_2-\text{CH}_2-\text{O}-\text{CH}_3+\text{HBr}\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{CH}_3-\text{CH}_2-\text{CH}_2\text{OH}+\text{CH}_3-\text{Br}\\\\ \ \ \ \ \ \ \text{n-Propylmethyl ether}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Propanol}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Bromomethane}$
View full question & answer→Question 421 Mark
Explain why is OH group in phenols more strongly held as compared to OH group in alcohols.
AnswerIn phenols, the -OH group is attached to $sp^2$ hybridised carbon of an aromatic ring. The carbon- oxygen bond length (136 pm) in phenol is slightly less than that in methanol. This is due to partial double bond character on account of the conjugation of unshared electron pair of oxygen with the aromatic ring whereas in alcohols, the oxygen of the -OH group is attached to carbon by a sigma bond formed by the overlap of a $sp^3$ hybridised orbital of carbon with a $sp^3$ hybridised orbital of oxygen. That is why -OH group in phenol is more strongly held as compared to alcohol.
View full question & answer→Question 431 Mark
Dipole moment of phenol is smaller than that of methanol. Why?
AnswerDue to electron withdrawing effect of phenyl group, the C-O bond in phenol is less polar, whereas in case of methanol the methyl group has electron releasing effect and hence C-O bond in it is more polar. Dipole moment depends upon the polarity of bonds.
View full question & answer→Question 441 Mark
While separating a mixture of ortho and para nitrophenols by steam distillation, name the isomer which will be steam volatile. Give reason.
AnswerIntramolecular H-bonding is present in o-nitrophenol. O-Nitrophenol is steam volatile because of weak intra molecular H-Bonding. In p-nitrophenol, the molecules are strongly associated due to the presence of intermolecular bonding. Hence, o-nitrophenol is steam volatile whereas p-nitrophenol is not.
View full question & answer→Question 451 Mark
Write structure of the compound whose IUPAC names are as follow:1 – Ethoxypropane.
Answer$\text{C}_2\text{H}_5\text{O}-\text{CH}_2-\text{CH}_2-\text{CH}_3$
View full question & answer→Question 461 Mark
Show how would you synthesise the following alcohols from appropriate alkenes?
Question 471 Mark
Name the alcohol that is used to make the following ester:
$ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O} \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ || \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{C}-\text{O}-\text{CH}-\text{CH}_3$
Answer$ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{|}\\\text{CH}_3-\text{CH}-\text{CH}_3$
View full question & answer→Question 481 Mark
Explain why propanol has higher boiling point than that of the hydrocarbon, butane?
AnswerPropanol has higher boiling point than butane because of wide spread H-bonding among propanol molecules. A lot of energy is required to break inter molecular H-bonding among propanol molecules. There is no such bonding in butane.
View full question & answer→Question 491 Mark
How can propan-2-one be converted into tert- butyl alcohol?
Answer$\ \ \ \ \ \ \ \ \ \ \ \ \ \text{O} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ {||} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \text{CH}_3 - \text{C} - \text{CH}_3 + \text{CH}_3\text{MgI}\xrightarrow{\text{Ether}}\text{CH}_3-\text{C}-\text{CH}_3\xrightarrow[\text{H}]{\text{H}_2\text{O}}\text{CH}_2-\text{C}-\text{CH}_3+\text{Mg(I)OH} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Addition Product} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{teri-Butyl alcohol} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (2-\text{Methylpropan}-2-\text{Ol})$
View full question & answer→Question 501 Mark
Show how are the following alcohols prepared by the reaction of a suitable Grignard reagent on methanal?$\text{CH}_3-\text{CH}-\text{CH}_2\text{OH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Answer
$\text{CH}_3-\text{CH}-\text{CH}_2\text{OH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Thus, Grignard reagent used is
$\text{CH}_3-\text{CH}-\text{MgBr}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$ View full question & answer→
