In the decimal form, fraction $\frac{25}{8}=3.125$
Answer
In order to convert fraction into decimal, we first convert it into an equivalent fraction with denominator $10$ or $100$ or $1000$ and then write its numerator and mark decimal point after one place or two place or three places from right towards left, if the denominator is $10$ or $100$ or $1000$ respectively. If the numerator is short of digits, insert zeroes at the left of the numerator. $\frac{25\times125}{8\times125}=\frac{3125}{1000}=3.125$
The decimal $3.725$ is equal to $3.72$ correct to two decimal places.
Answer
For correcting $3.725$ to two decimal places we look at the thousandths place.
Here, the digit at thousandths places is $5.$ So, the digit at hundredths place $2$ will be increased by $1$ and $5$ will be written as equal to zero.
Hence, $3.725 = 3.73 ($correct to two decimal places$)$
We have, $\frac{18}{39}=\frac{18\div3}{39\div3}[\because HCF$ of $18$ and $39$ is $3]$ $=\frac{6}{13}$ Note: A fraction is in its lowest terms, if its numerator and denominator have no common factor other than $1.$
The place value of a digit at the hundredths place is $\frac1{10}$ times the same digit at the ones place.
Answer
Let $0.11$ be a decimal number having same digits at ones and tenths place.
Now, the place value of $1$ at tenths place $\frac1{10}\ ...\text{(i)}$
The place value of $1$ at hundredths place $=\frac{1}{100}\ ...\text{(ii)}$
From Eqs. $(i)$ and $(ii),$ we get $\frac{1}{100}=\frac{1}{10}\times\frac{1}{10}$
$\therefore$ The place value of $1$ at hundredths place is $\frac{1}{10}$ times of $1$ at tenths place.
Here, the whole number part of both the decimal numbers is same.
Now, tenths part of $19.25=\frac{2}{10}$
And tenths part of $19.053=\frac{0}{10}$
Clearly, $\frac{0}{10}<\frac2{10}$
$\therefore19.25>19.053$
We have, $\frac{8}{18}-\frac{8}{15} LCM$ of $18$ and $15.$
$\begin{array}{c|c}2&18,15\\\hline3&9,15\\\hline3&3,5\\\hline5&1,5\\\hline&1,1\end{array}$
$\therefore LCM$ of $18$ and $15 = 2 \times 3 \times 3 \times 5 = 90.$
Now, converting the given fractions to equivalent fraction with denominator $90.$
$\frac{8\times5}{18\times5}=\frac{40}{90}$ and $\frac{8\times6}{15\times6}=\frac{48}{90}$
$\therefore\frac{40}{90}\frac{4}{7}$