MATHS M.C.Q. [1 Marks Each]

$90, 08, 00, 700 = 90x$
$1,00,00,000 + 08x$
$1,00,000 + 700$ Number name
will be ninety crore eight lakh seven hundred.

Place value of $5 = 5 \times 10000 = 50000$
Face value of $5 = 5$
$\therefore$ Required difference $= 50000 - 5 = 49995$

We have, $1729$
Prime factors of $1729$
$\begin{array}{c|c}7&1729\\ \hline13&247\\ \hline19&19\\ \hline&1\end{array}$
Thus, the prime factors of $1729 = 7 \times 13 \times 19$
Sum of the prime factors of $1729 = 7 + 13 + 19 = 39$

We know that $X = 10, C = 100$
Therefore, $XC = 100 - 10$

Numerical value will be $16 \times 1,00,00,000 + 04 \times 1,00,000 + 50 \times 1,000 + 310 = 160450310$

One lakh $(100000)$ is equal to one hundred thousand $(100,000).$

Between $1$ and $100,$ the digit $9$ occurs in $9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98$ and $99.$
$\therefore$ The digit occurs $20$ times between $1$ and $100.$

$7268$ will be rounded off to the nearest hundred as $7300.$
$2427$ will be rounded of to the nearest hundred as $2400.$
$\therefore 7300 - 2400 = 4900$

We know $1$ billion $= 100$ crores
Hence, the correct answer is option $(c).$

We know that $1$ meter $= 100\ cm$ so $160 / 100$
$= 1.6$ meters so ankit is $1.6$ meters tall

Since, the product of a non-zero whole number and its successor is always an even number, e.g.
$6 \times 7 = 42 13 \times 14 = 182$

The number formed using given digits are $769, 796, 976, 967, 679, 697$ Even numbers are $796, 976.$

Ten lakh ninety thousand nine hundred nine In numerals it can be written as, $10,90,90$

$1$ million $=1000000$
ten million $= 10 \times 1000000.$
$= 10000000$
$= 1$ crore

 Million period consists of the places $M, TM, HM.$

 We know that $1 \text{meter}={100}\text{cm}$
$1\text{cm}=\frac{1}{100}\text{m}$
$673\text{cm}=\frac{1}{100}\times673\text{m}$
$=\frac{673}{100}\times\text{m}$
$=6.73 \text {meter}$
It is equivalent to $6$ meters and $73\ cm.$

 We know $1$ million $= 10$ lakhs
$\therefore 10$ millions $= 10 \times 10$ lakhs $= 1$ crore
Hence, the correct answer is option $(b).$

$ LCM$ must be divisible by $HCF.$
Now, $180$ is not divisible by $75.$
e.g. Let the two numbers be $4$ and $8.$
Then, $HCF$ of $4$ and $8 = 4$ and $LCM$ of $4$ and $8 = 8$
$\therefore LCM + HCF = 8 + 4 = 2$

 The number is $1512.$ Its digit at the tens place is $1 < 5.$
So, the given number is rounded off to the nearest hundred as $1500.$

 The largest four-digit number $= 9999$
The smallest four-digit number $= 1000$
Total number of all four-digit numbers $= (9999 - 1000) + 1$
$= 8999 + 1$
$= 9000$

We know that $'V'$ stands for $'5'$ and $'X'$ stands for $'10'$ in Roman
So, we can not write $5$ before $10.$

 Let $x$ be any whole number.
According to the question,
$(x + 25) + (25 - x) = x + 25 + 25 - x = 50$

In international system of numeration
The $1st$ period consists of - ones, tens and hundred.
The $2nd$ period consists of - thousand, $10$ thousand and $100$ thousands.
The $3rd$ period consists of - million, $10$ million and $100$ million.
The $4th$ period consists of - billion, $10$ billion and $100$ billio.
$\therefore 648340021$ is written with commas as $($International System$) = 648,340,021$

The three distinct smallest digits are $0, 1$ and $2.$ To form a smallest number using these digits, we need to arrange them in ascending order, but by this we get $012,$ which results in a two-digit number. So, the smallest three-digit number having distinct digits is $102.$

The numbers that when rounded off to nearest tens give us $200$ are $195, 196, 197, 198, 199, 200, 201, 202, 203, 204.$

$M$ stands for thousand in roman numerals
$\therefore MMM = 3000$

$83, 07, 80, 120 = 83 \times 1,00,00,000 + 07\times 1,00,000 + 80 \times 1,000 + 120$
So this will equal to Eighty three crore seven lakh eighty thousand one hundred twenty

We know that
$1$ kilometer $= 1000\ m$
$1\text{m}=\frac{1}{1000}\text{km}$
Given that, we have to convert $6045m$ to kilometer
$6045\text{m}=\frac{1}{1000}\times6045\text{km}$
$=\frac{6045}{1000}\text{km}$
$= 6.045$ kilometer
or $= 6\ km \ 45\ m$

$88 , 789$ reads as Eighty eight thousand seven hundred eighty nine
$8$ is at ten thousands place, $8$ at thousands place, $7$ at hundreds place and so on.