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Question 12 Marks
An astronaut inside a small space ship orbiting around the earth cannot detect gravity. If the space station orbiting around the earth has a large size, can he hope to detect gravity?
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Question 22 Marks
The mass of a bicycle rider along with the bicycle is 100 kg . He wants to cross over a circular turn of radius 100 m with a speed of $10 ms^{-1}$. If the coefficient of friction between the tyres and the road is 0.6 , will the rider be able to cross the turn? Take $g =10 ms^{-2}$.
Answer
The centripetal force acting on the bicycle is given by,
$
\begin{aligned}
& F_{C}=\frac{m v^2}{r} \\
& =\frac{100 \times 10 \times 10}{100} \\
& =100 N
\end{aligned}
$
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Question 32 Marks
A small spherical ball of radius r falls with velocity v through a liquid having coefficient of viscosity $\eta$. Find the viscous drag F on the ball assuming it depends on $\eta, r$ and v . Take $K =6 \pi$.
Answer
Let $F =K \eta^a r^b v^c$, then
$
\begin{aligned}
& M^1 L^1 T^{-2}=\left[ML^{-1} T^{-1}\right]^{a}[L]^{b}\left[LT^{-1}\right]^{c} \\
& =M^{a} L^{-a+b+c} T^{-a-c} \\
& \therefore a=1,-a+b+c=1,-a-c=-2
\end{aligned}
$
On solving, $a = b = c =1$
Hence $F =K \eta r v=6 \pi \eta r v$ (Stoke's law)
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Question 42 Marks
In CGS system, the value of Stefan's constant is $\sigma=5.67 \times 10^{-5} erg s ^{-1} cm^{-2} K^{-4}$. Find its value in SI units. Given $1 J=10^7 erg$.
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Question 52 Marks
If earth has a mass 9 times and radius twice that of a planet Mars, calculate the minimum velocity required by a rocket to pull out of the gravitational force of Mars. Take the escape velocity on the surface of earth to be 11.2 $kms ^{-1}$.
Answer
Here, $M_e=9 M_m$, and $R_e=2 R_m$
$v _{ e }$ (escape speed on surface of Earth) $=11.2 km / s$
Let $V_m$ be the speed required to pull out of the gravitational force of mars.
We know that
$
v_{e}=\sqrt{\frac{2 G M_e}{R_e}} \text { and } v_m=\sqrt{\frac{2 G M_m}{R_m}}
$
Dividing, we get $\frac{v_m}{v_e}=\sqrt{\frac{2 G M_m}{R_m} \times \frac{R_e}{2 G M_e}}$
$
\begin{aligned}
& =\sqrt{\frac{M_m}{M_e} \times \frac{R_e}{R_m}}=\sqrt{\frac{1}{9} \times 2}=\frac{\sqrt{2}}{3} \\
& \Rightarrow v_m=\frac{\sqrt{2}}{3}(11.2 km / s)=5.3 km / s
\end{aligned}
$
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Question 62 Marks
What are longitudinal waves? Give examples too.
Answer
Longitudinal waves are the waves in which medium particles vibrate to and fro about their mean positions along a straight line parallel to the direction of wave propagation. In a longitudinal wave, each particle of matter vibrates about its normal rest position and along the axis of propagation, and all particles participating in the wave motion behave in the same manner, except that there is a progressive change in phase of vibration-i.e.,each particle completes its cycle of reaction at a later time. The combined motions result in the advance of alternating regions of compression and rarefaction in the direction of propagation. Waves setup in springs, waves set up in air columns (organ pipes), sound waves, transfer of motion from the engine to last bogey (or wagon) in a train etc., are common examples of longitudinal waves.
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