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Physics 1 Marks Question

PART - 2 CH - 13 Oscillations · Rajasthan Board (RBSE) STD 11 Science (Rajasthan - English Medium). 39 questions.

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1 Marks Question

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39 questions · timed · auto-graded

Question 11 Mark
The following example represent periodic motion :
An arrow released from a bow.
Answer
(d) It is not a periodic motion.
$\because$ The movement of an arrow released from the bow is on a parabolic path and is not repeated.
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Question 21 Mark
The following example represent periodic motion :
A hydrogen molecule rotating about its centre of mass.
Answer
This is a periodic motion
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Question 31 Mark
The following example represent periodic motion :
A freely suspended bar magnet displaced from its N-S direction and released.
Answer
This is a periodic motion because a freely sus pended magnet, once displace from the N-S direction, oscillates on either side of the mean position. Hence this is also simple harmonic motion.
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Question 41 Mark
The following example represent periodic motion :
A swimmer completing one (return) trip from one bank of a river to the other and back.
Answer
It does not represent periodic motion because the swimmer moves between fixed point, but his time
is not fixed.
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Question 51 Mark
Why is the necessary for a pendulum performing simple harmonic motion that its amplitude be less than its length?
Answer
Since $T=2 \pi \sqrt{\frac{l}{g}}$ in the formula of that $(\sin \theta=$ $\theta$ ) hence it is true only when $\theta$ is very small i.e. the dimension is less in comparison to the length
$ \because \quad \theta=\frac{\text { dimension }}{\text { length }} $
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Question 61 Mark
Write the value of restoring force in a simple pendulum, when the angle of displacement is small.
Answer
$\begin{array}{l}\text { Restoring force } F =m g \sin \theta \\ \quad \theta \text { is less. } \quad \because \sin \theta=\theta \\ \therefore \text { Restoring force }= F =m g \theta\end{array}$
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Question 71 Mark
If the acceleration of a particle simple $a=\left(-\frac{p}{q}\right) x$ harmonic motion is given, then what will be the time period of this particle?
Answer
Period $T =2 \pi \sqrt{\frac{q}{p}} l$.
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Question 81 Mark
A girl is swinging if the girl starts steep swinging, what will be the effect on the period?
Answer
The period will decrease. Since the center of mass will rise while standing, the effective length will reduce due to which the time period will decrease.
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Question 91 Mark
What is the relationship between the total energy and oscillation frequency of a simple pendulum?
Answer
$\begin{aligned} \text { Total energy } & =\frac{1}{2} m \omega^2 A^2 \\ \text { But } \omega & =2 \pi n \\ \text { Total energy } & =\frac{1}{2} m(2 \pi n)^2 A^2=2 \pi^2 m n^2 A^2\end{aligned}$
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Question 101 Mark
What is the relationship between acceleration and displacement for simple harmonic motion?
Answer
Acceleration $a \propto$ displacement.
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Question 111 Mark
A man wearing a watch is falling down from a tower, will the watch show the correct time?
Answer
Yes, because the wrist watch depends on the functioning of the spring and g has no effect on it.
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Question 121 Mark
From where is the restoring force obtained for simple harmonic oscillation in a spring?
Answer
Restoring force is obtained
Simple Pendulum-Gravitational acceleration
Spring-Elasticity.
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Question 131 Mark
The oscillator of a pendulum is negatively charged and a positively charged conductor plate is placed below it. The pendulum is made to oscillate. What will be the effect on the time period of the pendulum?
Answer
Attraction due to electric field between oscillator and plate. It will take force. Therefore, the effective value of g will increase, due to which the period will decrease.
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Question 141 Mark
At what position is the restoring force maximum on a particle performing simple harmonic motion?
Answer
At extreme position
$ F=-k x=-k A $
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Question 151 Mark
What will be the frequency of a pendulum hanging in the cabin, when falling freely?
Answer
The value of acceleration on freely objects is zero. Hence the frequency will also be zero.
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Question 161 Mark
Write the acceleration, displacement and frequency of particle performing simple harmonic motion.
Answer
Acceleration $a=\omega^2 y$
$\text {or}\quad\quad\quad\quad a=(2 \pi n)^2 y=4 \pi^2 n^2 y $
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Question 171 Mark
Why does a pendulum clock not work in an artificial earth satellite?
Answer
Oscillations do not occur due to weightlessness.
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Question 181 Mark
What will the effect on time period if a hollow sphere of the same size is used instead of a solid iron sphere in a simple pendulum.
Answer
Will remains unchanged. Since the period does not depend on the mass of sphere.
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Question 191 Mark
A complete oscillation by a particle performing simple harmonic motion how much work is completed in?
Answer
Zero
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Question 211 Mark
The total energy of particle remains in simple harmonic motion.
Answer
Total energy $E =\frac{1}{2} m \omega^2 A^2$ remains constant.
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Question 221 Mark
Frequency of oscillations of a mass $M$ hanging from a spring $n_1$. If the length of the spring is cut to half, the same mass again oscillates with frequency $n_2$. Find the value of $\frac{n_2}{n_1}.$
Answer
$\frac{n_2}{n_1}=\sqrt{2}$
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Question 231 Mark
Ifa 1kg weight is hung from a light spring, it makes 4 oscillations in 1 second. If a 4 kg weight is hung from the same spring, how many oscillations will it make per second?
Answer
It will make two oscillations per second.
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Question 241 Mark
Under the condition is the minimum restoring force on a particle moving in simple harmonic motion?
Answer
In a state of equilibrium.
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Question 251 Mark
If the mass M is hung on a spring and it gets extended a distance x. What will be the magnitude of the force constant of that spring?
Answer
The magnitude of the force constant of the spring will be $\frac{m g}{x}$
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Question 261 Mark
If the potential energy at any position of a particle performing simple harmonic motion is half of the total energy, then what will be the displacement at that position?
Answer
$0-707~ \text {amplitude}$ 
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Question 271 Mark
The total energy of a simple pendulum is E. What will be the kinetic energy and potential energy of the pendulum at the instant when the displacement of the pendulum is half of the amplitude?
Answer
Kinetic energy $=\frac{3 E }{4}$, Potential energy $=\frac{E}{4}$
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Question 281 Mark
What is the time difference between displacement and acceleration in simple harmonic motion ?
Answer
$\pi$ or $180^{\circ}$
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Question 291 Mark
If the oscillation amplitude of a simple pendulum is reduced to half of its present value, then what will be the value of its time period?
Answer
Will remain unchanged. Since the period does not depend on the amplitude.
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Question 301 Mark
Write the relationship between acceleratoin, displacement and frequency of a particle performing simple harmonic motion?
Answer
$a=-4 \pi^2 n^2 y =-\omega^2 y$
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Question 311 Mark
What will be the effect on the time period if a gold sphere of the same size is used instead of an iron sphere in a simple pendulum?
Answer
Will remains unchanged. Since there is no change in the effective lengrth, for this reason the period will remain unchanged.
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Question 321 Mark
What is the spring constant when the length of spring is $\frac{1}{n}$ ?
Answer
It will increase n times.
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Question 331 Mark
When the simple pendulum experiment is performed on Mount Abu the acceleration due to gravity reduce by 1%, what should be the change in the pendulum length to get the correct time from the pendulum clock?
Answer
These will be 91% decrease in the pendulum length.
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Question 341 Mark
If 0-1 kg the dimension of the body is 3 cm and if the oscillation period is 2 seconds, then what will be the value of total mechanical energy?
Answer
Total energy $=\frac{1}{2} m \omega^2 A^2$
$ \begin{aligned} & =\frac{1}{2} m(2 \pi n)^2 A^2 \\ & =\frac{1}{2} m\left(\frac{2 \pi}{T}\right)^2 A^2 \because n=\frac{1}{T} \\ \text { Keeping value } & =\frac{1}{2} \times 0.1\left(\frac{2 \pi}{2}\right)^2 \times(0.03)^2 \\ & =\frac{1}{2} \times 0.1 \times \pi^2 \times(0.03)^2 \text { Joule } \end{aligned} $
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Question 351 Mark
What will be the effect on the period of oscillation if a soft spring of the same length is used in place of a hard spring?
Answer
Will increase. Since the time period
$T =2 \pi \sqrt{\frac{m}{k}}$
The value of k for a soft spring is less than that for a hard spring.
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Question 371 Mark
In simple harmonic motion by what phase angle is value of the displacement ahead of its acceleration value?
Answer
That is, simple harmonic motion the value of displacement is ahead of its acceleration by phase angle.
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Question 381 Mark
In a harmonic motion the initial phase is $\phi=\frac{3 \pi}{16}$. Express it in terms of period T .
Answer
The initial phase angle is $\phi=\frac{3}{32} T \because T =2 \pi$.
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Question 391 Mark
What is the initial phase angle of a body starting simple hormonic motion from the terminal end?
Answer
$\frac{\pi}{2}$
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