Question 11 Mark
A graph of potential energy V(x) verses x is shown in a particle of energy E0 is executing motion in it. Draw graph of velocity and kinetic energy versus x for one complete cycle AFA.
Answer
View full question & answer→- KE versus x graph, By the law of conservation of energy. Total Mechanical energy
E = KE + PE
E0 = KE + V(x)
K.E. = E0 - V(x)
At point A
PE is maximum,
PE = E0 ; background:rgba(220,220,220,0.5))
KE = E0 - E0 = 0
At B, x = 0, PE = VB(let)
KE = E0 - V0
At C, x = x1, PE = 0
KE = E0 - V(x)
= E0 - 0 = E0
At D, x = x2, KE = E0
At E, x = x3, PE = E0
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KE = 0
Figure shows graph KE versus x.
| X | KE | Point |
| 0 | 0 | A |
| 0 | E1 | B |
| x1 | E0 | C |
| x2 | E0 | D |
| x3 | 0 | F |
- Velocity (v) versus (x),
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; background:rgba(220,220,220,0.5))
| Point | v | x |
| A | 0 | 0 |
| B | | 0 |
| C | ; background:rgba(220,220,220,0.5)) | x1 |
| D | ; background:rgba(220,220,220,0.5)) | x2 |
| E | 0 | x3 |
At point A and F.
and ; background:rgba(220,220,220,0.5))
At C and D, ; background:rgba(220,220,220,0.5))
; background:rgba(220,220,220,0.5))
; background:rgba(220,220,220,0.5))
(v - x) graph is shown in given figure here.