Question 12 Marks
(a) Calculate $\Delta G^{0}$ for the reaction
$Zn(s) + Cu^{2+}(aq) \longrightarrow Zn^{2+}(aq) + Cu(s)$.
Given: $E^{0}$ for $Zn^{2+}/Zn = -0.76 V$ and
$E^{0}$ for $Cu^{2+}/Cu = +0.34 V$,
$R = 8.314 J K^{-1} mol^{-1}$,
$F = 96500 C mol^{-1}$.
(b) Give two advantages of fuel cells.
$Zn(s) + Cu^{2+}(aq) \longrightarrow Zn^{2+}(aq) + Cu(s)$.
Given: $E^{0}$ for $Zn^{2+}/Zn = -0.76 V$ and
$E^{0}$ for $Cu^{2+}/Cu = +0.34 V$,
$R = 8.314 J K^{-1} mol^{-1}$,
$F = 96500 C mol^{-1}$.
(b) Give two advantages of fuel cells.
Answer
View full question & answer→(a) $E ^{\circ}{ }_{\text {cell }}= E ^{\circ}{ }_{ L }- E ^{\circ}{ }_{ A }$
$=0.34-(-0.76)=1.10 V$
$\Delta G ^{\circ}=-n FE ^{\circ}$
$=-2 \times 1.10 \times 96500$
$=-212300 J / mol$
$=-212.3 kJ / mol$
(b) (i) Pollution free, (ii) High efficiency.
$=0.34-(-0.76)=1.10 V$
$\Delta G ^{\circ}=-n FE ^{\circ}$
$=-2 \times 1.10 \times 96500$
$=-212300 J / mol$
$=-212.3 kJ / mol$
(b) (i) Pollution free, (ii) High efficiency.