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Question 12 Marks
a. Differentiate between Ideal solution and Non-ideal solution.
b. 30 g of urea is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg.
Answer
(a)
Ideal SolutionNon-ideal solution
The solution obeys Raoult's law at all concentrations.The solution does not obey Raoult's law.
$\Delta V$ mixing $=0$ and $\Delta H_{\text {mixing }}=0$$\Delta V _{\text {mixing }} \neq 0$ and $\Delta H _{\text {mixing }} \neq 0$

(b)
$
\frac{P_{A}^0-P_{A}}{P_{A^o}^o}=\frac{\frac{W_{B}}{M_{B}}}{\frac{W_{B}}{M_{B}}+\frac{W_{A}}{M_{A}}}
$$1-\frac{ P _{ A }}{23 \cdot 8}=\frac{\frac{30}{60}}{\frac{846}{18}}$ or $1-\frac{ P _{ A }}{23 \cdot 8}=\frac{\frac{30}{60}}{\frac{846}{18}+\frac{30}{60}}$
$P _{ A }=\frac{46.5}{47} \times 23.8=23.5 mm Hg$ or vapour pressure of the solution $P _{ A }=\frac{47}{47.5} \times 23.8=23.5 mm Hg$
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Question 22 Marks
Write the formula of the following complexes:
$i.$ Hexaammine platinum $(IV)$ chloride.
$ii.$ Dichloro tetrammine cobalt $(III)$ ion.
Answer
$1. [Pt(NH_3)_6]Cl_4$
$2. [CoCl_2(NH_3)_4]^+$
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Question 42 Marks
If the density of some lake water is $1.25\ g\ mL^{-1}$ and contains $92\ g$ of $Na^+$ ions per kg of water, calculate the molarity of $Na^+$ ions in the lake.
Answer
$\text { Molar mass of } N a=23\ g\ mol ^{-1}$
$\text { No. of moles of } Na ^{+}=\frac{92 g}{232\ g\ mol -1}=4 mole$
$\text { Density }=\frac{\text { Mass }}{\text { Volume }}$
$V=\frac{\text { Mass }}{\text { density }}=\frac{1000}{1.25}(g)$
$V=800 ml$
$\text { Molarity }=\frac{\text { Number of moles }}{\text { Volume }( ml )} \times 1000$
$\text { Molarity }=\frac{4 \times 1000}{800}=5\ moles $
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Question 52 Marks
Answer the following:
$(a)$ The rate of a reaction is given by rate $= k [N_2O_5].$ In this equation what does $k$ stand for?
$(b)$ Is it possible to determine or predict the rate law theoretically by merely looking at the equation?
Answer
Answer the following:
$(i)\ 'k\ '$ stands for rate constant of a reaction.
$(ii)$ The rate law is experimentally determined. It cannot be predicted by merely looking at the balanced chemical equation.
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Question 62 Marks
Give reasons for the following:
$a.$ The only oxidation state shown by Scandium is $+3.$
$b.\ [Ti(H_2O)_6]^{4+}$ is colourless.
$c.$ MnO is basic while $Mn_2O_7$ is acidic.
Answer
$a.\  At + 3$ oxidation state, Stable $d^\circ$ is obtained
$b.$ Absence of unpaired electron / no d-d transition occurs
$c.\ MnO$ has $Mn$ in $+2$ Oxidation State
$Mn_2O_7$ has $Mn$ in $+7$ Oxidation State. Higher the Oxidation State, Higher is the acidic character.
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