Question 12 Marks
The magnetic field in a plane electromagnetic wave is given by $B_y=\left(2 \times 10^{-7}\right) T \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right)$.
(a) What is the wavelength and frequency of the wave?
(b) Write an expression for the electric field.
(a) What is the wavelength and frequency of the wave?
(b) Write an expression for the electric field.
Answer
View full question & answer→(a) Comparing the given equation with
$
B_y=B_0 \sin \left[2 \pi\left(\frac{x}{\lambda}+\frac{t}{T}\right)\right]
$
We get, $\lambda=\frac{2 \pi}{0.5 \times 10^3} m =1.26 cm$, and
$
\frac{1}{T}=\nu=\left(1.5 \times 10^{11}\right) / 2 \pi=23.9 GHz
$
(b) $E_0=B_0 c=2 \times 10^{-7} T \times 3 \times 10^8 m / s =6 \times 10^1 V / m$
The electric field component is perpendicular to the direction of propagation and the direction of magnetic field. Therefore, the electric field component along the $z$-axis is obtained as $E_z=60 \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right) V / m$
$
B_y=B_0 \sin \left[2 \pi\left(\frac{x}{\lambda}+\frac{t}{T}\right)\right]
$
We get, $\lambda=\frac{2 \pi}{0.5 \times 10^3} m =1.26 cm$, and
$
\frac{1}{T}=\nu=\left(1.5 \times 10^{11}\right) / 2 \pi=23.9 GHz
$
(b) $E_0=B_0 c=2 \times 10^{-7} T \times 3 \times 10^8 m / s =6 \times 10^1 V / m$
The electric field component is perpendicular to the direction of propagation and the direction of magnetic field. Therefore, the electric field component along the $z$-axis is obtained as $E_z=60 \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right) V / m$

Radius of each circular plate $, R = 6.0 \ cm = 0.06 m$ Capacitance of a parallel plate capacitor $, C = 100 pF = 100 \times 10^{-12} F$ Supply voltage $, V = 230 V$ Angular frequency $, ω = 300 \ \text{rad s}^{-1} $