Question 12 Marks
An electric dipole of dipole moment $2\times10^{-6}cm$ is kept inside a closed surface. What will be the net flux coming out from the surface ?
Answer
View full question & answer→Dipole Moment $P=2\times10^{-6}$ cm
Gauss's rule,
$\phi=\frac{q_{in}}{\in_{0}}$ [Net Flux $q_{in}=+q-q=0]$
Or $\phi=\frac{0}{\in_{0}}=0$
$\frac{p}{+q \quad-q}$
So Net Flux will be zero.
Gauss's rule,
$\phi=\frac{q_{in}}{\in_{0}}$ [Net Flux $q_{in}=+q-q=0]$
Or $\phi=\frac{0}{\in_{0}}=0$
$\frac{p}{+q \quad-q}$
So Net Flux will be zero.
