Question
A capacitor with capacitance C is changed to potential V. What is its electrical energy ?

Answer

Electrical energy of capacitor
$U=\frac{Q^{2}}{2C}$ ...(1)
Where $Q=CV$
In equation (1) the value of Q
$U=\frac{(CV)^{2}}{2C}$
$U=\frac{1}{2}CV^{2}$

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