Physics M.C.Q (1 Marks)

When a charged particles moves in a uniform magnetic field in a direction perpendicular to the field, then the path of the particle will be:

Moving charge produces:

The toroid of radius 10 cm has 100 turns. If a current of 0.1 ampere is flowing in it, then the value of the magnetic field on the axis of the toroid will be:

A constant current is flowing through a long straight conductor, then the graph showing change in produced magnetic field B with distance r is:

A moving coil galvanometer can be converted into voltmeter by:

The reason for attractive force between two parallel wires in which current is flowing in same direction is:

To convert a moving coil galvanometer into voltmeter

Magnitude of produced magnetic field at any point inside a solenoid depends on:

Current is flowing in two parallel good conducting wires in the same direction. They will

Two independent parallel wires in which the current is flowing in the same direction. They will:

In an area of constant magnetic field, a charged particle enters in a direction parallel to the direction of magnetic field with its velocity. The speed of particle is:

Nature of electron beam travelling in same direction with same velocity is:

An electron moves with a constant velocity v in a uniform magnetic field B, parallel to the direction of the magnetic field. The force acting on electron is:

Two long straight wires are kept parallel, distance between them is 2R and current is flowing in opposite directions in two wires. The magnitude of magnetic field at a point midway between them which is at a distance R from each wire is:

Direction of magnetic field at any point due to a long current carrying conductor is:

Current I is flowing in a wire of infinite length. Magnetic field is B at a perpendicular distance r from the wire. The correct relation is:

Magnitude of intensity of magnetic field at the center of any circular current carrying conductor is:

Magnetic field in a current carrying solenoid is B. If length of the solenoid and current flowing through the solenoid is doubled, keeping the number of turns same, the magnitude of magnetic field in the solenoid will be:

Correct mathematical form of Ampere's rule is:

Magnitude of magnetic field for a definite cross-section of a current carrying toroid is:

Current of 1 A is flowing through two parallel wires in the same direction and distance between the wires is 1 m . The mutual attractive force at unit length will be :

Same current is flowing through two identical coils. Their centers are common and their planes are mutually perpendicular. Magnetic field at the center due to one coil is B then the resultant magnetic field at the common center is :

An electron rotating in a circular path of radius r making n revolutions per second. Magnetic moment of electron will be: