Question 11 Mark
A particle starts from a point A and travels along the solid curve shown in figure. Find approximately the position B of the particle such that the average velocity between the positions A and B has the same direction as the instantaneous velocity at B.


Answer
View full question & answer→At position B instantaneous velocity has direction along $\overrightarrow{\text{BC}}.$ For average velocity between A and B.$\text{V}_{\text{ave}}=\frac{\text{displacement}}{\text{times}}=\Big(\frac{\overrightarrow{\text{AB}}}{\text{t}}\Big)$
t = time We can see that $\overrightarrow{\text{AB}}$ is along $\overrightarrow{\text{BC}}$ i.e. they are in same direction. The point is B(5m, 3m).
t = time We can see that $\overrightarrow{\text{AB}}$ is along $\overrightarrow{\text{BC}}$ i.e. they are in same direction. The point is B(5m, 3m).




