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M.C.Q. [1 M]

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Question 11 Mark
The slope of a speed-time graph gives:
Answer
  1. Acceleration.
Explanation:
The rate of change of speed per unit time is termed as acceleration.
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Question 21 Mark
A freely falling object travels 4.9m in 1st second, 14.7m in 2nd second, 24.5m in 3rd second, and so on. This data shows that the motion of a freely falling object is a case of:
Answer
  1. Uniform acceleration.
Explanation:
The displacement of the body in equal interval of time is unequal, but acceleration is constant. The acceleration will thus be uniform.
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Question 31 Mark
Suppose a boy is enjoying a ride on a merry$-$go$-$round which is moving with a constant speed of $10 \ ms^{-1}.$ It implies that the boy is:
Answer
The speed is constant but velocity is not constant, because its direction goes on changing i.e., there is acceleration in the motion. So, we can say that the boy is in accelerated motion.
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Question 41 Mark
The numerical ratio of displacement to distance for a moving object is:
Answer
  1. Equal to 1 or less than 1
Explanation:
Displacement is always smaller than or equal to displacement.
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Question 51 Mark
In a free fall the velocity of a stone is increasing equally ion equal intervals of time under the effect of gravitational force of the earth. Then what can you say about the motion of this stone? Whether the stone is having:
Answer
  1. Uniform acceleration.
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Question 61 Mark
Suppose a boy is enjoying a ride on a merry-go-round which is moving with a constant speed of $10m\ s^{–1}.$ It implies that the boy is:
Answer
In merry-go-round, the speed is constant but velocity is not constant, because its direction goes on changing i.e., there is acceleration in the motion.
So, we can say that the boy is in accelerated motion.
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Question 71 Mark
The splash is heard $2.05s$ after the stone is dropped into a well of depth $19.6m.$ The velocity of sound is?
Answer
$392ms^{−1}$​​​​​​​
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Question 91 Mark
If a bus travelling at $20\ m/ s$ is subject to a steady deceleration of $5\ m/s^2,$ how long will it take to come rest:
Answer
Using first equation of motion
$v = u + at,$ we have
$0 = 20 + (−5)t$
$\Rightarrow 5t = 20$
$\Rightarrow t = 4s$
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Question 101 Mark
A man is $25m$ behind a bus, when bus starts accelerating at $2 \ m/ s^2$ and man starts moving with constant velocity of $10 \ m/ s.$ Time taken by him to board the bus is $........$?
Answer
$5s$
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Question 121 Mark
The graph below shows the distance travelled and the time taken by four cars.
Which car travelled the slowest:
Answer
  1. Car 4
Explanation:
The slope of the distance-time graph represents the velocity.
The slope for the car 4 is minimum, so its speed is also minimum.
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Question 131 Mark
Which of the following situations are not possible?
Answer
  1. A body moving with a constant velocity in an accelerated motion.
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Question 141 Mark
The slope of displacement-time graph being negative implies
Answer
  1. That the object moves towards the reference point
Explanation:
Negative slope of a displacement-time graph indicates negative velocity.
Velocity is measured negative when a body moves towards the reference point.
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Question 151 Mark
A body was initially moving with $10 \ m$ sec and it starts acceleration with $2 \ m/ sec^2,$ the distance covered by it in $10$ sec will be
Answer
$200m$
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Question 161 Mark
What is the speed of a train which overtakes, a man walking at a speed of 5 km/ h in 30 seconds, if the train is 274 metres long?
Answer
  1. 37.88 km/ h
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Question 171 Mark
Direction of motion of a body is given by:
Answer
  1. Its velocity
Explanation:
Velocity is a vector.
So, it gives the magnitude of speed and the direction of motion of the body as well.
Speed being a scalar, does not give the direction of motion.
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Question 181 Mark
A stone is thrown vertically up from the ground. It reaches a maximum height of 50m in 10s. After what time will it reach the ground from the maximum height?
Answer
  1. 10s
Explanation:
$\text{t}_\text{a}=\frac{\text{u}}{\text{g}}=10\text{s}$
same amount of time it will take to fall down
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Question 191 Mark
Which of the following statement is correct regarding velocity and speed of a moving body?
Answer
  1. Velocity of a moving body is its speed in a given direction.
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Question 211 Mark
Leaves are the food factories of plant”. But, how does cactus (desert plants) carry out photosynthesis?
Answer
  1. Stems
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Question 221 Mark
A particle starts from the origin at $t = 0s$ with a velocity of $10.0j\ m/ s$ and moves in the $xy−$plane with a constant acceleration of the $ms^{−2}.$ Then $y−$coordinate of the particle in $2$ sec is
Answer
$24\ m$
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Question 241 Mark
When speed is stated along with its direction, it is called as:
Answer
  1. Velocity
Explanation:
Velocity of a body is the speed of the body defined along with the direction.
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Question 251 Mark
A $100m$ sprinter increases her speed from rest uniformly at the rate of $1m/s2$ upto $40m$ and covers the remaining distance with a uniform speed. The sprinter covers the first half of the run in $t1s$ and second half in $t2s,$ then.
Answer
For the first 40mUsing the third equation of motion:$ v^2 - u^2 = 2as$
where: s $=$ distance covered $= 40mv =$ final velocity $=$ ? $m/su =$ initial velocity $= 0m/sa =$ acceleration $= 1m/s^2$
$v^2 - u^2 = 2as$
$v^2 - 0 = 2 \times 1 \times 40$
$v^2 = 80$
$v = 8.94m/s$
Using the first equation of motion $v = u + at$
where:
$v =$ final velocity $= 8.94m/s$
$u =$ initial velocity $= 0m/sa =$ acceleration $= 1m/s^2$
$t_1 =$ time $=$ ?s
$v = u + at_1$
$8.94 = 0 + 1 \times t_1$
$t_1 = 8.94s$
Here its given the speed is uniform not velocity, therefore
acceleration will be $1m/s^2$ and speed will be $8.94m/s$ everywhere.
Using the third equation of motion: $v^2 - u^2 = 2as$
where
$s =$ distance covered
$= 60mv =$ final velocity $=$ ??$m/su$
$=$ initial velocity $= 8.94m/sa$
$=$ acceleration $= 1 m/s^2$
$v^2 - u^2 = 2as$
$v^2 - (8.94)^2 = 2 \times 1 \times 60$
$v^{2 }- 80 = 120$
$v^2 = 120 + 80 = 200$
$v = 14.14m/s$ Using the first equation of motion
$v = u + at$
where:
$v =$ final velocity $= 14.14m/s$
$u =$ initial velocity $= 8.94m/sa =$ acceleration $= 1m/s^2$
$t_2 =$ time $=$ ?s
$v = u + at_2$
$14.14 = 8.94 + 1 \times t_2$
$t_2 = 14.14 - 8.94$
$t_2 = 5.2\  secs.$
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Question 261 Mark
Starting from rest objects 1 falls freely for 4 seconds and object 2 falls freely for 8 seconds.Compared to object 1, object 2 falls
Answer
  1. Four times as far
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Question 271 Mark
When two bodies moves uniformly towards each her then they cross each other at the speed of $10\ m/s.$ If both the bodies move in the same direction, then they cross each other at the speed of $6\ m/s.$ The speed of both bodies are:
Answer

Let the objects speed be $x$ and $y$ respectively, when moving towards each other:
$x + y = 10 ...(1)$
and, when moving in same direction
$x - y = 6 ...(2)$
now,
adding $1$ and $2$ we get
$2x = 16\ m/s$
$x = 8\ m/s$
and,
putting this in $1$
$y = 2\ m/s$
The speed of the bodies is $8\ m/s^2$ and $2\ m/s^2.$

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Question 281 Mark
Uniform circular motion is called continuously accelerated motion mainly because its:
Answer
  1. Direction of motion changes
Explanation:
An accelerating body is an object that is changing its velocity.
And since velocity is a vector that has both magnitude and direction, a change in either the magnitude or the direction constitutes a change in the velocity.
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Question 291 Mark
Name a physical quantity that remains constant in a uniform circular motion:
Answer
  1. Angular speed
Explanation:
As an object moves around in a circle at constant speed (uniform circular motion), both the velocity and the acceleration change.
The magnitudes of the velocity and acceleration don't change, but since velocity and acceleration are vectors, the fact that their directions change means that they change.
Momentum is directly proportional to the velocity of the body and hence it changes.
In the uniform circular motion, the angular speed is same for all the particles,
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Question 321 Mark
Which of the following is most likely not a case of uniform circular motion?
Answer
  1. Motion of a racing car on a circular track.
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Question 331 Mark
Which of the following terms does not go well with the motion of a bus on a crowded road:
Answer
  1. Uniform velociity
Explanation:
On a crowded road, depending on traffic conditions, the bus driver has to change its speed and direction of motion many times.
The driver will have to frequently apply brakes as well.
He might also have to accelerate the bus with different rates.
So, the velocity changes both by magnitude and direction.
Thus, uniform velocity is not attained in this case.
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Question 341 Mark
If the displacement of an object is proportional to square of time, then the object moves with:
Answer
  1. Uniform acceleration.
Explanation:
Velocity is measured in terms of distance per second, while acceleration is measured in terms of distance per square second.
Hence, uniform acceleration is the correct answer.
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Question 351 Mark
A particle is moving in positive x-direction with initial velocity of 10m/ s and uniform retardation such that it reaches the initial position after 10s. he distance traversed by the particle in 6s is:
Answer
  1. 26m
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Question 361 Mark
A Negative charge is moving towards a person. The direction of magnetic field lines will be in:
Answer
  1. Clockwise direction.
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Question 371 Mark
A heavy stone is thrown from a cliff of height h with speed v. The stone will hit the ground with maximum speed if it is thrown:
Answer
  1. The speed does not depend on the inital direction
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Question 381 Mark
A body thrown vertically up reaches a maximum height of 50m.Another body with double the mass is thrown up with double the initial velocity will reach a maximum height of :
Answer
  1. 200m
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Question 391 Mark
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
Answer
  1. $\frac{\text{u}^2}{2\text{g}}$
Explanation:
A body is thrown vertically upward.
at maximum height velocity of body = 0
use kinematics formula ,
v² = u² + 2as 
Here,
v = 0
a = -g
s = H
0 = u² - 2gH
$\text{H}=\frac{\text{u}^2}{2\text{g}}$
Hence, maximum height attained by body $\frac{\text{u}^2}{2\text{g}}$
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Question 401 Mark
When an object is accelerated:
Answer
  1. Its velocity is necessarily changing
Explanation:
Acceleration is the time rate of change of velocity.
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Question 411 Mark
A bus is travelling the first one-third distance at a speed of 10km/h, the next one-fourth at 20km/h and the remaining at 40km/h. What is the average speed of the bus?
Answer
  1. 18km/h.
Explanation:
If total distance is S then
Average speed
$=\frac{\text{Total distance}}{\text{time}}$
$=\frac{\text{S}}{(\text{t}_{1}+\text{t}_{2})}$
$=\text{S}\ \frac{\text{S}}{(3\times10)}+\frac{\text{S}}{(4\times20)}+\frac{5\text{S}}{(12\times40)}$
$\therefore\text{Time}=\frac{\text{Distance}}{\text{Speed}}$
$=\frac{1}{\big(30+1\frac{1}{80}+\frac{5}{480}\big)}=17.7\text{kmph}$
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Question 421 Mark
If north is the positive direction, which situation involves positive velocity and negative acceleration:
Answer
  1. A car slowing down as it moves northward
Explanation:
The rate of change of velocity with respect to time is known as acceleration.
Negative acceleration means a decrease in velocity with respect to time.
If a car is moving northward and slowing down, the displacement will be along the north (positive), so the velocity will be positive until it gets stopped.
As the car is slowing down, the acceleration will be negative.
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Question 431 Mark
Choose the correct option.Odometer: Distance :: ______:______?
Answer
  1. Weighing scale: Weight
Explanation:
An odometer is an instrument used in a vehicle to measure the distance covered by it.
Similarly, the weighing scale is an instrument used to measure the weight of an object.
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Question 441 Mark
In which of the following cases of motions, the distance moved and the magnitude of displacement are equal?
Answer
  1. If the car is moving on straight road.
Explanation:
In all other class, displacement can be less than distance.
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Question 461 Mark
You are sitting in a stationary car. There is a helium balloon tied to its floor. You accelerate and obviously feel like you are being pushed backwards (against the direction of your accelerations). The balloon.
Answer
  1. Will move forward.
Explanation:
The densest air in your passenger compartment is the ambient air. The least dense is your helium-filled balloon. When you accelerate, the ambient air will try to remain where it is and will appear to "slosh" toward the rear (if you can see the ambient air). Because the balloon has less inertia, it will be displaced by the heavier ambient air and will be forced forward in the passenger compartment.
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Question 481 Mark
A water drop falls at regular intervals from a tap 9m above the ground. The fourth drop is leaving the tap at the instant, the first drop touches the ground. How high is the third drop at that instant?
Answer
  1. 8m
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Question 491 Mark
A body moving along a straight line at 20 metre per second undergoes an acceleration of 4 metre per second square. After 2 second it speed will be:
Answer
  1. 28 metre per second
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Question 501 Mark
Is it possible for an object's velocity to increase while its acceleration decreases?
Answer
  1. Yes, an example would be a falling object in a viscous medium, where the acceleration continuously decreases but velocity increases until a certain point.
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M.C.Q. [1 M] - Science STD 9 Questions - Vidyadip