MCQ 11 Mark
A boy “A” of mass 50 kg climbs up a staircase in 10 s. Another boy “B” of mass 60 kg climbs up a Same staircase in 15s. The ratio of the power developed by the boys “A” and “B” is
- ✓$\frac{5}{4}$
- B$\frac{3}{2}$
- C$\frac{4}{5}$
- D$\frac{2}{3}$
Answer
View full question & answer→Correct option: A.
$\frac{5}{4}$
$\frac{5}{4}$
Solution:Work done by the boy 'A' $\left( W _1\right)=m_1 g h=50 g h$Work done by the boy 'B' $\left( W _2\right)=m_2 g h=60 g h$Power developed by$A = P _1=\frac{w_1}{t_1}=\frac{50 g h}{10}$ Power developed by $B =$ is $\quad P _2=60 gh / 15$. then, $p_1 / p_2=\frac{50 gh / 10}{60 gh / 15}=\frac{5}{4}$
Solution:Work done by the boy 'A' $\left( W _1\right)=m_1 g h=50 g h$Work done by the boy 'B' $\left( W _2\right)=m_2 g h=60 g h$Power developed by$A = P _1=\frac{w_1}{t_1}=\frac{50 g h}{10}$ Power developed by $B =$ is $\quad P _2=60 gh / 15$. then, $p_1 / p_2=\frac{50 gh / 10}{60 gh / 15}=\frac{5}{4}$

