MATHS M.C.Q. [1 Marks Each]

$ 0.25=\frac{25}{100}=\frac{1}{4}$

$1.007 - 0.7 = 1.007 - 0.700 = 0.307$

Consider the fractions $\frac{7}{12}$ and $\frac{4}{21}$
Prime factorisation of $12 = 2 \times 2 \times 3$
Prime factorisation of $21 = 3 \times 7$
$\therefore LCM$ of $12$ and $21 = 2 \times 2 \times 3 \times 7 = 84$
Firstly, convert the fractions to equivalent fractions with denominator 84
$\Rightarrow\frac{7}{12}=\frac{7\times7}{12\times7}=\frac{49}{84}$
$\Rightarrow\frac{4}{21}=\frac{4\times4}{21\times4}=\frac{16}{84}$
Now,
$49>16$
$\therefore\ \frac{49}{84}>\frac{16}{84}$
$\frac{7}{12}>\frac{4}{21}$

$ \frac{232}{990}$ is equal to $0.234$

In order to find the product, we first multiply $2$ by $5$
We have, $2 \times 5 = 10$
Now, $0.02$ has $2$ decimal places is $ 2+ 2 = 4$
So, the product must contain $4$ places of decimals.
$\therefore 0.02 \times 0.05= 0.0010$
$= 0.001$

To find the decimal value of a fraction we just divide the numerator of the fraction by the denominator.
Here, numerator $= 48$ And denominator $= \frac{100048}{1000}=48;0.048$

 $9275$ meters in $km,$ as decimal fraction $\frac{9275}{1000}\text{km}=\text{9.275 km}$ 

 Apples used on monady $=\frac{4}{5}\ \text{of}\ 5=\frac{4}{5}\times5=4\text{kg}$
Remaining apples $= 5 - 4 = 1\ kg$
Apples used next day $=\frac{1}{3}$ of remaining apples
$=\frac{1}{3}\times1\text{kg}=\frac{1}{3}\text{kg}$
So, weight of aplles left now
= Total apples-Apples use monday-Apples used next day
$=\big(-4-\frac{1}{3}\big)$
$=\frac{15-12-1}{3}$ $\big[\text{taking LCM}\big]$
$=\frac{2}{3}\text{kg}$

 Since, $ 0.004=\frac{0.004}{1}$
Now, Multiply both numerator and denominator by $1000.$
$ \frac{0.004\times1000}{1\times1000}$$= \frac{4}{1000}$

$ 25.369$
In this, $5$ lies on ones place.
$ \therefore$ Place value of $ 5=5\times{1}=5$

To find the percent of a given number, we will multiply it with $100$.
Let the number in decimal be $x$ When converted to percent, the number becomes $ \text{x}\times 100=62.9\Rightarrow\text{x}=\frac{62.9}{100}$
$ \Rightarrow\text{x}=0.629$

$=3 \times 0.3 \times 0.03 \times 0.003 \times 30$
$=3\times\frac{3}{10}\times\frac{3}{100}\times\frac{3}{1000}\times3\times10$
$=\frac{3\times3\times3\times3\times3}{100\times1000}$
$=\frac{243}{100000}$
$=0.00243 ($Decimal point is shifted to left by $5$ places$)$

Since, $ 0.012=\frac{0.012}{1}$
Now, Multiply both numerator and denominator by $1000$
$ \frac{0.012\times1000}{1\times1000}$ $= \frac{12}{1000}$

$2\frac{2}{25}=\frac{52}{25}=\frac{52\times4}{25\times4}$
$=\frac{208}{100}=2.08$

We have
$0.012\div0.15=\frac{0.012}{0.15}=\frac{0.012\times100}{0.15\times100}$
$=\frac{1.2}{15}=0.08$

 We know that,
$1\text{g}=\frac{1}{1000}\text{kg}$
Now,
$5\text{kg }5\text{g}=5\text{kg}+5\text{g}$
$=5\text{kg}+\frac{5}{1000}\text{kg}$
$=5\text{kg}+0.005\text{kg}$
$=5.005\text{kg}$
$\therefore\ 5\text{kg }5\text{g}$
$=5.005\text{kg}$

$0.4 \times 0.4 \times 0.4 = 0.064$

We know that a fraction is in its lowest terms if its numerator and denominator have no common factor other than $1.$
Thus, if the fraction $\frac{\text{a}}{\text{b}}$ is in its lowest terms, then the $HCF$ of a and b is $1.$

$\frac{105}{112}$ is reducible fraction because $HCF$ $112$ of $105$ and $112$ is $7$

$\Big(5\frac{1}{4}-3\frac{1}{3}\Big)$
$=\frac{21}{4}-\frac{10}{3}$
$=\frac{21\times3}{4\times3}-\frac{10\times4}{3\times4} (LCM$ of $3$ and $4$ is $12)$
$=\frac{63}{12}-\frac{40}{12}$
$=\frac{63-40}{12}$
$=\frac{23}{12}$
$=1\frac{11}{12}$

Decimal means divide the numerator by the denominator.
Here, Numerator $= 4999$ and
Denominator $= 1000\Rightarrow \frac{4999}{1000}=4.999$

The first decimal digit from the decimal point is the tenth.
$4.4$ has $4$ on the ones, after decimal point on the tenths is $4$ tenths.
$4.4$ is the sum of $4$ and $\frac{4}{10}$ or $\frac{44}{10}.$

$0.5\times0.05=\frac{5}{10}\times\frac{05}{100}=\frac{25}{1000}$
$=0.025$

$ \text{4}\frac{7}{11} = \frac{4\times11 + 7}{11} = \frac{51}{11}$

$2\text{kg} 5\text{g} = (2 \times 1000)\text{g} + 5\text{g} = (2005)\text{g}$
$=\Big(\frac{2005}{1000}\Big)\text{kg}=2.005\text{kg}$

A decimal is a fractional number and is indicated by digits after a period which is called a decimal point. Tenths have one digit after the decimal point. The decimal $0.8$ is pronounced as eight tenths. Hundredths have two digits after the decimal point. The decimal $0.06$ is pronounced as six hundredths. Thousandths follow a similar pattern. They have three digits after the decimal point. The decimal $0.005$ is pronounced as five thousandths. Hence, five thousandths is $0.005.$

$2.73\div1.3=\frac{2.73}{1.3}$
$=\frac{273\times10}{13\times100}=\frac{273}{130}=\frac{21}{10}=2.1$

$=24.125$
$=24+0.125$
$=24+0.1+0.02+0.005$
$=24+\frac{1}{10}+\frac{2}{100}+\frac{5}{1000}$
Comparing this the given expression, we get
$\text{A}=1,\text{B}=2$ and $\text{C}=5$
$\therefore\ \text{A}+\text{B}+\text{C}=1+2+5$
$\text{A}+\text{B}+\text{C}=8$

To find the percent of a given number, we will multiply it with $100$ Let the number in decimal be $x$
When converted to percent,
the number becomes $ \text{x} \times100=0.002,$
which gives $ \text{x}=0.00002.$