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97 questions · 1 auto-graded MCQ + 96 self-marked written.

Question 11 Mark
Read statement below carefully, and state, with reasons, if it is true or false: During rolling, the force of friction acts in the same direction as the direction of motion of the CM of the body.
Answer
False. Explanation: Frictional force acts opposite to the direction of motion of the centre of mass of a body. In the case of rolling, the direction of motion of the centre of mass is backward. Hence, frictional force acts in the forward direction.
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Question 21 Mark
Read statement below carefully, and state, with reasons, if it is true or false: For perfect rolling motion, work done against friction is zero.
Answer
True. Explanation: When perfect rolling begins, the frictional force acting at the lowermost point becomes zero. Hence, the work done against friction is also zero.
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Question 31 Mark
Read statement below carefully, and state, with reasons, if it is true or false: A wheel moving down a perfectly frictionless inclined plane will undergo slipping (not rolling) motion.
Answer
True.Explanation:
The rolling of a body occurs when a frictional force acts between the body and the surface. This frictional force provides the torque necessary for rolling. In the absence of a frictional force, the body slips from the inclined plane under the effect of its own weight.
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Question 41 Mark
Read statement below carefully, and state, with reasons, if it is true or false: The instantaneous acceleration of the point of contact during rolling is zero.
Answer
False. Explanation: When a body is rolling, its instantaneous acceleration is not equal to zero. It has some value.
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Question 51 Mark
Read statement below carefully, and state, with reasons, if it is true or false: The instantaneous speed of the point of contact during rolling is zero.
Answer
True. Explanation: Rolling can be considered as the rotation of a body about an axis passing through the point of contact of the body with the ground. Hence, its instantaneous speed is zero.
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Question 61 Mark
A cylinder of mass $10\ kg$ and radius $15\ cm$ is rolling perfectly on a plane of inclination $30^\circ$ . The coefficient of static friction $\mu_\text{s}= 0.25$
  1. How much is the force of friction acting on the cylinder?
  2. What is the work done against friction during rolling?
  3. If the inclination $\theta$ of the plane is increased, at what value of $\theta$ does the cylinder begin to skid, and not roll perfectly?
Answer
Mass of the cylinder, $m = 10\ kg$ Radius of the cylinder, $r = 15\ cm = 0.15m$ Co$-$efficient of kinetic friction, $\mu_\text{k}= 0.25$ Angle of inclination, $\theta=30^\circ$ Moment of inertia of a solid cylinder about its geometric axis, $\text{I}=\Big(\frac{1}{2}\Big)\text{mr}^2$ The various forces acting on the cylinder are shown in the following figure: The acceleration of the cylinder is given as, $\text{a}=\frac{\text{mg}\sin\theta}{\Big[\text{m}+\big(\frac{\text{I}}{\text{r}^2}\big)\Big]}$
$=\frac{\text{mg}\sin\theta}{\Bigg[\text{m}+\Bigg\{\Bigg(\frac{\frac{1}{2}\text{mr}^2}{\text{r}^2}\Bigg)\Bigg\}\Bigg]}$
$=\Big(\frac{2}{3}\Big)\text{g}\sin30^\circ$
$=\Big(\frac{2}{3}\Big)\times9.8\times0.5=3.27\text{ms}^{-2}$ Using Newton’s second law of motion, we can write net force as, $\text{f}_\text{net}=\text{ma}$
$\text{mg}\sin30^{\circ}-\text{f}=\text{ma}$
$\text{f}=\text{mg}\sin30^{\circ}-\text{ma}$
$=10\times9.8\times0.5-10\times3.27$
$49-32.7=16.3\text{N}$ During rolling, the instantaneous point of contact with the plane comes to rest. Hence, the work done against frictional force is zero. For rolling without skid, we have the relation, $\mu=\Big(\frac{1}{3}\Big)\tan\theta$
$\tan\theta=3\mu=3\times0.25$
$\therefore\ \theta=\tan^{-1}(0.75)=36.87^\circ$
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Question 71 Mark
Two masses M, and M, separated by distance r start moving towards each other due to their own force of attraction. What will be the change in centre of mass?
Answer
Since no external force acts, the centre of mass will stay where it is.
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Question 81 Mark
In a fly wheel, most of the mass is concentrated at the rim. Explain why?
Answer
Concentration of mass at the rim increases the moment of inertia and thereby brings uniform motion.
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Question 91 Mark
Moment of inertia of uniform circular disc about a diameter is I. What is the moment of inertia about an axis perpendicular to its plane and passing through a point on its rim?
Answer
Applying theorem of parallel axes, MI about the given axis $=\frac{1}{2}\text{MR}^2+\text{MR}^2=\frac{3}{2}\text{MR}^2$ $=6\times\frac{1}{4}\text{MR}^2=61$
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Question 101 Mark
When the earth shrinks, without reducing its mass, what change will be there in the duration of a day?
Answer
L is conserved. If the earth shrinks, duration of the day decreases.
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Question 111 Mark
Does the radius of gyration depend upon the speed of rotation of the body?
Answer
No, it depends only on the distribution of mass of the body.
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Question 121 Mark
A rectangular brick is kept on a table with a part of its length projecting out. It remains at rest if the length projected is slightly less than half the total length but it falls down if the length projected is slightly more than half the total length. Give reason.
Answer
The centre of mass (CM) of a rectangular block lies in the middle of the block. When the block is projected less than half of its length (CM being over the table), no net force acts on it. Thus, no net torque acts upon the body.But if the block is projected more than half of its length outside the table (CM being outside the table), gravitational force acts along the CM of the block. This force produces a moment along the edge of the table. This rotates the block, and as a result, it falls down.
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Question 131 Mark
Explain how a cat is able to land on its feet after a fall taking advantage of the principle of conservation of angular momentum.
Answer
While falling a cat stretches its body along with the tail so that its moment of inertia (I) increases. As no external torque acts, L = Iw = constant. As I increases, w decreases and it lands gently on its feet.
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Question 141 Mark
Why is the head of screw made wide?
Answer
The head of a screw is made wide so as to have a greater torque for the applied force.
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Question 151 Mark
How will you distinguish between a hard boiled egg and a raw egg by spinning each on a table top?
Answer
To distinguish between a hard boiled egg and a raw egg, we spin each on a table top. The egg which spins at a slower rate shall be a raw egg. This is because in a raw egg, liquid matter inside tries to get away from the axis of rotation. Therefore, its moment of inertia I increases. As $\tau=\text{I }\alpha=$ constant, therefore, a decreases, i.e., raw egg will spin with smaller angular acceleration. The reverse is true for a hard boiled egg which will rotate more or less like a rigid body.
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Question 161 Mark
A ring and a circular disc of different materials have equal masses and equal radii. Which one will have a larger moment of inertia about an axis passing through its centre of mass perpendicular to its plane?
Answer
A ring has a larger moment of inertia because its entire mass is concentrated at the rim at the maximum distance from the axis.
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Question 171 Mark
If the angular momentum of a body is found to be zero about a point, is it necessary that it will also be zero about a different point?
Answer
No, angular momentum is dependent on the position vector of the particle, angle between the radius vector and the linear velocity of the particle. So, there may be finite angular momentum along any different point even if it is zero at a particular point. If angular momentum is zero along O but finite along O.
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Question 181 Mark
Two satellites of equal masses, which can be considered as particles, are orbiting the earth at different heights. Will their moments of inertia be same or different?
Answer
Different. The satellite at larger height has more moment of inertia. Since $I = mass \times (distance)^2$.
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Question 191 Mark
What are the factors on which moment of inertia of a body depend?
Answer
Moment of inertia of a body depends upon:
  1. Mass of the body.
  2. Shape and size of body.
  3. Position of the axis of rotation.
  4. Distribution of mass in the body about the axis of rotation.
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Question 201 Mark
What are the units and dimensions of moment of inertia? Is it a vector quantity?
Answer
The units of moment of inertia are $\mathrm{kgm}^2$ and its dimensional formula is $[\mathrm{M}^{'} \mathrm{L}^2\mathrm{T}^0]$. No, it is not a vector quantity.
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Question 211 Mark
Where does the centre of mass of a uniform triangular lamina lie?
Answer
It lies at the centroid of the triangular lamina, i.e., where the three medians of the triangular lamina intersects.
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Question 231 Mark
Find the torque of a force $7\hat{\text{i}}-3\hat{\text{j}}-5\text{k}$ about the origin which acts on a particle whose position vector is $\hat{\text{i}}+\hat{\text{j}}-\hat{\text{E}}.$
Answer
$\vec{\text{F}}=7\hat{\text{i}}-3\hat{\text{j}}-5\hat{\text{k}}$ $\vec{\text{r}}=\hat{\text{r}}+\hat{\text{j}}-\hat{\text{k}}$ $\vec{\tau}=\vec{\text{r}}\times\vec{\text{F}}=(\hat{\text{i}}+\hat{\text{j}}-\hat{\text{k}})\times(7\hat{\text{i}}-3\hat{\text{j}}-5\hat{\text{k}})$ $=-8\hat{\text{i}}-2\hat{\text{j}}-10\hat{\text{k}}$
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Question 241 Mark
If the ice on the polar caps of the earth melts, how will it affect the duration of the day? Explain.
Answer
Earth rotates about its polar axis. When ice of polar caps of earth melts, mass concentrated near the axis of rotation spreads out. Therefore, moment of inertia I increases. As no external torque acts, $\therefore\text{L}=\text{I}\omega=\text{I}\Big(\frac{2\pi}{\text{T}}\Big)$ = Constant. With increase of I, T will increase, i.e., length of the day will increase.
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Question 261 Mark
Write an expression for the work done in rotator motion.
Answer
Work done $=\int_\limits{\theta\text{i}}^\limits{\theta\text{f}}\tau\text{ d}\theta$
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Question 271 Mark
Write an expression for the velocity of the centre of mass of particles.
Answer
Velocity of centre of mass of all body system is $\text{V}_{\text{cm}}=\frac{\text{m}_1\text{v}_1+\text{m}_2\text{v}_2+\dots+\text{m}_{\text{n}}\text{v}_{\text{n}}}{\text{m}_1+\text{m}_2+\dots+\text{m}_{\text{n}}}$ $=\frac{\sum^\limits{\text{n}}_\limits{\text{i}=1}\text{m}_{\text{i}}\text{v}_{\text{i}}}{\sum^\limits{\text{n}}_\limits{\text{i}=1}\text{m}_{\text{i}}}$
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Question 281 Mark
State the condition for translational equilibrium of a body.
Answer
For translational equilibrium of a body net force acting on it i.e., the vector sum of all the forces acting on the body must be zero.
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Question 291 Mark
If a cube is melted and is casted into a sphere, does moment of inertia about an axis through centre of mass increases or decreases.
Answer
Moment of inertia of a sphere is less than that of a cube of same mass.
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Question 301 Mark
Why are we not able to rotate a wheel by pulling or pushing along its radius?
Answer
Torque to rotate is not created by pushing or pulling along its radius.
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Question 311 Mark
State the condition for rotational equilibrium of a body.
Answer
For rotational equilibrium of a body the vector sum of torques of all the forces acting on the body about the reference point must be zero.
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Question 321 Mark
If earth were to shrink suddenly, what would happen to the length of the day?
Answer
Length of the day reduces as earth shrinks.
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Question 331 Mark
What are the factors on which moment of inertia of a body depends?
Answer
Moment of inertia of a body depends on position and orientation of axis of rotation. It also depends on shape, size of the body and also on the distribution of mass of the body about the given axis.
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Question 341 Mark
Which component of a force does not contribute towards torque?
Answer
The radial component of a force does not contribute towards torque.
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Question 351 Mark
Does the moment of inertia of a rigid body change with the speed of rotation?
Answer
No, because the moment of inertia depends upon the axis of rotation and distribution of mass.
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Question 361 Mark
Why is it easier to balance a bicycle in motion?
Answer
The wheel does not fall as long as the angular momentum remains constant. Due to friction angular momentum changes and when the wheel stops, it comes to unstable equilibrium.
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MCQ 371 Mark
A sphere can roll on a surface inclined at an angle $\theta$ if the friction coefficient is more than $\frac{2}{7}\text{g}\sin\theta$ Suppose the friction coefficient is $\frac{1}{2}\text{g}\sin\theta$ and a sphere is released from rest on the incline,
  • A
    It will stay at rest.
  • It will translate and rotate about the centre.
  • C
    It will make pure translational motion.
  • D
    The angular momentum of the sphere about its centre will remain constant.
Answer
Correct option: B.
It will translate and rotate about the centre.
As coefficient of friction is less than the one required for rolling, therefore the sphere will slip i.e., ii will translate and rotate about the centre.
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Question 381 Mark
What is moment of inertia of a solid sphere about its diameter?
Answer
$\text{I}=\frac{2}{5}\text{MR}^2,$ where M is the mass and R is radius of the solid sphere.
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Question 391 Mark
Why is moment of inertia also called rotationa inertia?
Answer
The moment of inertia gives a measure of inertia in rotational motion. So, it is also called rotational inertia.
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Question 401 Mark
Does the radius of gyration depend on the angular velocity of the body?
Answer
$\text{No. K}=\sqrt{\frac{\text{I}}{\text{M}}}$
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Question 421 Mark
Does the centre of mass of a solid necessarily lie within the body? If not, give an example.
Answer
No, the centre of mass of L-shaped rod lies in the region outside of rod.
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Question 431 Mark
Can a body in translatory motion have angular momentum?
Answer
Yes, A particle in translatory motion always has an angular momentum, unless the point (about which angular momentum is calculated) lies on the line of motion.
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Question 441 Mark
What is moment of inertia of a hollow sphere about an axis passing through its centre?
Answer
$\text{I}=\frac{2}{5}\text{MR}^2,$ where M is the mass and R is radius of the hollow sphere.
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Question 451 Mark
Write two factors on which center of mass of a body does not depend.
Answer
Two factors on which centre of mass of a body does not depend.
  1. Choice of coordinate system.
  2. Rotatory motion of a body.
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Question 461 Mark
Why does a pilot not fall down when his aeroplane takes a vertical loop?
Answer
Weight provides necessary centripetal force at the highest point.
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Question 471 Mark
A labourer standing near the top of an old wooden step ladder feels unstable. Why?
Answer
The point of contact of the ladder with the ground is the point about which the ladder can rotate. When the labourer is at the top of the ladder, the lever arm of force is large. So, the turning effect can be large.
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Question 491 Mark
If all the particle of a system lie in a cube, is it neccesary that the centre of mass be in the cube?
Answer
Yes in case cube is uniform in that case center of mass should be inside cube.
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Question 501 Mark
If no external torque act on a body, will its angular velocity remain conserved?
Answer
No, Angular velocity is not conserved but angular momentum is conserved.
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Question 511 Mark
In a rotating body, $\text{a}=\alpha\text{r}$ and $\text{v}=\omega\text{r}.$ Thus $\frac{\text{a}}{\alpha}=\frac{\text{v}}{\omega}.$ Can a co you use the theorems of ratio and proportion studied in algebra so as to write $\frac{\text{a}+\alpha}{\text{a}-\alpha}=\frac{\text{v}+\omega}{\text{v}-\omega}$
Answer
No, we cannot use componendo-dividendo theorem of proportion here. This is because $\alpha$ and a, and v and $\omega$ are dimensionally different. Therefore, ​$\text{v}+\omega$ and/ or $\alpha+\text{a}$ are not possible.
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Question 521 Mark
What is the moment of inertia of a sphere of mass 20kg and radius m about its diameter?
Answer
Moment of inertia of a sphere about its diameter, $\text{I}=\frac{2}{5}\text{mR}^2=\frac{2}{5}\times\Big(\frac{1}{4}\Big)^2$ $=0.5\text{kg}-\text{m}^2$
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Question 531 Mark
What is the position vector of centre of mass of two particles of equal masses?
Answer
For two equal masses, the centre of mass lies at the mid-point of the line joining them. $\vec{\text{r}}_{\text{cm}}=\frac{\vec{\text{r}}_1+\vec{\text{r}}_2}{2}$
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Question 541 Mark
Why do we place handles at maximum possible distance from the hinges in a door?
Answer
To develop torque with less force being applied.
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Question 551 Mark
A cylinder of mass $10\ kg$ and radius $15\ cm$ is rolling perfectly on a plane of inclination $30^\circ$ . The coefficient of static friction $\mu_\text{s}= 0.25$
  1. How much is the force of friction acting on the cylinder?
  2. What is the work done against friction during rolling?
  3. If the inclination $\theta$ of the plane is increased, at what value of $\theta$ does the cylinder begin to skid, and not roll perfectly?
Answer
Mass of the cylinder, $m = 10\ kg$ Radius of the cylinder, $r = 15\ cm = 0.15m$ Co$-$efficient of kinetic friction, $\mu_\text{k}= 0.25$ Angle of inclination, $\theta=30^\circ$ Moment of inertia of a solid cylinder about its geometric axis, $\text{I}=\Big(\frac{1}{2}\Big)\text{mr}^2$ The various forces acting on the cylinder are shown in the following figure: The acceleration of the cylinder is given as, $\text{a}=\frac{\text{mg}\sin\theta}{\Big[\text{m}+\big(\frac{\text{I}}{\text{r}^2}\big)\Big]}$
$=\frac{\text{mg}\sin\theta}{\Bigg[\text{m}+\Bigg\{\Bigg(\frac{\frac{1}{2}\text{mr}^2}{\text{r}^2}\Bigg)\Bigg\}\Bigg]}$
$=\Big(\frac{2}{3}\Big)\text{g}\sin30^\circ$
$=\Big(\frac{2}{3}\Big)\times9.8\times0.5=3.27\text{ms}^{-2}$ Using Newton’s second law of motion, we can write net force as, $\text{f}_\text{net}=\text{ma}$
$\text{mg}\sin30^{\circ}-\text{f}=\text{ma}$
$\text{f}=\text{mg}\sin30^{\circ}-\text{ma}$
$=10\times9.8\times0.5-10\times3.27$
$49-32.7=16.3\text{N}$ During rolling, the instantaneous point of contact with the plane comes to rest. Hence, the work done against frictional force is zero. For rolling without skid, we have the relation, $\mu=\Big(\frac{1}{3}\Big)\tan\theta$
$\tan\theta=3\mu=3\times0.25$
$\therefore\ \theta=\tan^{-1}(0.75)=36.87^\circ$
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Question 561 Mark
A ballet dancer stretches her hand out for slowing down. Name the conservation obeyed.
Answer
This is based on the principle of conservation of angular momentum.
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Question 571 Mark
Should there necessarily be any mass at centre of mass of system?
Answer
No, the centre of mass of a ring lies at its centre.
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Question 581 Mark
A hollow sphere, a solid sphere, a disc and a ring all having same mass and radius are rolled down on an inclined plane. If no slipping takes place, which one will take the smallest time to cover a given length?
Answer
The body with the smallest moment of inertia will roll down taking the smallest time. Here, the solid sphere has the lowest moment of inertia among all the other bodies. So, it will roll down taking the least time.
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Question 591 Mark
Can centre of mass of a body coincide with geometrical centre of the body?
Answer
Yes, when the body has a uniform mass density.
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Question 601 Mark
In a flywheel, most of the mass is concentrated at the rim. Explain why?
Answer
Concentration of mass at the rim increases the moment of inertia and thereby brings uniform motion.
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Question 611 Mark
What is the torque provided by a force acting through the centre of mass of a sphere?
Answer
Zero. Since $\tau = \text{r}_\bot\text{F}$ and $\text{r}_\bot=0$ for all points on the axis.
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Question 631 Mark
A simple pendulum is a point mass suspended by a light thread from a fixed point. The particle is displaced towards one side and then released. It makes small oscillations. Is the motion of such a simple pendulum a pure rotation? If yes, where is the axis of rotation?
Answer
Yes, it is an example of pure rotation. The axis of rotation passes through the pivot of the pendulum, perpendicular to the plane containing the pendulum.
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Question 641 Mark
A particle moves in a circular path with decreasing speed. What happens to its angular momentum?
Answer
Decreases in magnitude and remains the same in direction (along the axis).
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Question 651 Mark
It is easier to revolve a stone by attaching it to a shorter string rather than to a longer one. Why?
Answer
The tension required to maintain the mass increases with the length of the string.
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Question 661 Mark
A pair of equal and opposite forces acting on a body along two different lines of action constitute a _________.
Answer
A pair of equal and opposite forces acting on a body along two different lines of action constitute a couple.
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Question 671 Mark
Torque acting on a body is equal to rate of change of _______.
Answer
Torque acting on a body is equal to rate of change of angular momentum.
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Question 681 Mark
What is the angular velocity of the hour hand of clock?
Answer
Angular velocity of hour hand $\omega=\frac{2\pi}{12\text{hour}}$ $=\frac{2\pi}{12\times3600}\frac{\text{radius}}{\text{sec}}$
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Question 691 Mark
A body is said to be _______ if it does not change its shape and size when external force acts on it.
Answer
A body is said to be rigid if it does not change its shape and size when external force acts on it.
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Question 701 Mark
A wheel of moment of inertia $50 \mathrm{~kg}-\mathrm{m}^2$ about its own axis is revolving at a rate of 5 revolutions per second. What is its angular momentum?
Answer
Here, $I = 50 \mathrm{~kg}-\mathrm{m}^2$,$\omega=5\text{rps}=5\times2\pi\text{rad/s}$
$\therefore$ Angular momentum $\text{L}=\text{I}\omega=50\times10\pi\ 500\pi\text{J-s}$
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Question 721 Mark
The algebraic sum of the moments of masses of various particles of a system about its centre of mass is _______.
Answer
The algebraic sum of the moments of masses of various particles of a system about its centre of mass is zero.
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Question 731 Mark
Is centre of mass same as the centre of gravity of a body? How can a rigid body be balanced?
Answer
For smaller dimensions, they coincide. A rigid body can be balanced by applying a force equal and opposite to its weight at the centre of gravity.
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Question 741 Mark
When a sphere of radius $r$ rolls with its $\text{COM}$ having a linear velocity $v$, what is the velocity of $(i)$ the lower$-$most point in contact with the surface and $(ii)$ the top$-$most point?
Answer
  1. At lower most point, $v = 0$.
  2. Velocity will be $2v$ at top$-$most point.
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Question 751 Mark
Define moment of inertia and give its SI unit.
Answer
Moment of Inertia is defined as the sum of the products of constituent masses and the square of perpendicular distance from the axis of rotation. If $\mathrm{m}_1 \mathrm{~m}_2, \ldots$. are the masses at a perpendicular distances $\mathrm{r}_1, \mathrm{r}_2, \ldots, \mathrm{r}_{\mathrm{n}}$ In the moment of Inertia. $\text{I}=\text{m}_1\text{r}_1^2+\text{m}_2\text{r}_2^2+\dots\text{m}_{\text{n}}\text{r}_{\text{n}}^2$ $\sum\limits^\text{n}_{\text{i}=1}\text{m}_\text{i}\text{r}^2_\text{i}$ Its SI unit is $\mathrm{kgm}^2$
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Question 761 Mark
A ladder is at rest with its upper end against a wall and the lower end on the ground. Is the ladder more likely to slip, when a man stands on it at the bottom or at the top? Give reason.
Answer
It is more likely to slip when a man stands at the top of the ladder. This is due to the fact that the man's weight will provide an extra torque for the slipping of the ladder.
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Question 771 Mark
A sphere rolls on a horizontal surface. If there any point of the sphere which has a vertical velocity?
Answer
Some points on the equator of the sphere has got vertical velocity with respect to the direction of motion of the sphere.
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Question 781 Mark
Which component of linear momentum does not contribute to angular momentum?
Answer
Radial component of linear momentum.
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Question 791 Mark
The density of a rod AB continuously increases from A to B. Is it easier to set it in rotation by clamping it at A and applying a perpendicular force at B or by clamping it at B and applying the force at A?
Answer
It will require more force to set the bar into rotation by clamping at A and then clamping at B.

Explanation: Since the rod has mass density increasing towards B, the Center of Mass (CM) of the rod is near $B$. If the rod is clamped along A , the distance of CM of the rod from the pivot will be greater when the rod is clamped along B. Greater distance of CM from the Center of rotation increases the moment of inertia of the rod and hence more torque will be necessary to rotate the bar about A . Greater torque implies greater force will be necessary to rotate it. $\mathrm{F}_{\mathrm{A}}=$ Force required to rotated the rod clamped at $A . \mathrm{R}_A=$ Distance of CM from pivot $A . M=$ Mass of the rod. $F_B=$ Force required to rotate the rod clamped at $B$. $R_B=$ Distance of $C M$ from pivot $B$. We have $R_A>R_B$. We have to find the torque required to rotate rod clamped at $A$ to produce angular acceleration $a . T_A=M R_A^2 a=R_A F_A \Rightarrow F_A=$ $M R_{A a}$ We have to find torque required to rotate rod clamped at $B$ to produce angular acceleration $a . T_B=M R_B{ }^2 a=$ $R_B F_B \Rightarrow F_B=M R_{B a}$ On comparing, since $R_A>R_B$, we get: $F_A>F_B$
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Question 801 Mark
Centre of mass of a triangular lamina is at the point of intersection of the is _______.
Answer
Centre of mass of a triangular lamina is at the point of intersection of the is medians.
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Question 811 Mark
Two satellites of equal masses are orbiting at different heights. Will their moments of inertia be the same or different?
Answer
The moments of inertia will be different on account of different distances.
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Question 821 Mark
When do we call a body rigid?
Answer
When the separation between any two masses consistiting does not vary, the body is said to be rigid.
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Question 841 Mark
Should the centre of mass of a body necessarily lie inside the body? Explain.
Answer
No, it may lie outside the body. In case of semicircular ring, it is at the centre which is outside the ring.
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Question 851 Mark
A faulty balance with unequal arms has its beam horizontal. Are the weights of the two pans equal?
Answer
They are of unequal mass. Their masses are in the inverse ratio of the arms of the balance.
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Question 861 Mark
If all the particles of a system lie in X-Y plane, is it necessary that the centre of mass be in X-Y plane?
Answer
Yes in the case when all of particles are on same axis the center of mass would also lie on the same axis.
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Question 871 Mark
Explain why the speed of a whirl wind in a tornado is alarmingly high.
Answer
In a whirl wind, air from nearby regions gets concentrated in a small space. Moment of inertia (I) decreases on account of decrease in distance. As $\text{L}=\text{I}\omega,$ = Constant, therefore, angular speed o increases to alarming high values.
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Question 891 Mark
A rifle barrel has a spiral groove which imparts spin to the bullet. Why?
Answer
Angular momentum gained by the bullet provides better accuracy.
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Question 901 Mark
A constant torque of 120N-m rotates its point of action by an angle of 30°. What is the work done by the torque?
Answer
Work done by the torque, $\text{W}=\text{t}\theta$$=120\times\Big(\frac{30\times\pi}{180}\Big)=20\pi\text{J}.$
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Question 911 Mark
If the sum of all the forces acting on a body is zero, is it necessarily in equilibrium? If the sum of all the forces on a particle is zero, is it necessarily in equilibrium?
Answer
No, if the sum of all the forces acting on a body is zero, the body is not necessarily in equilibrium. To be in equilibrium, the sum of torque acting on the body must be zero too. In the above case, although the sum of the forces acting on the body is zero $\Big(\vec{\text{F}}_1+\Big(-\vec{\text{F}}_1\Big)=0\Big).$ Still, the body will rotate along $\overrightarrow{\text{OP}}.$ So, it won't remain in equilibrium.
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Question 921 Mark
Can the mass of body be taken to be concentrated at its centre of mass for the purpose of calculating its rotational inertia?
Answer
No, the moment of inertia greatly depends on the distribution of mass about the axis of rotation.
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Question 931 Mark
Is radius of gyration of a body a constant quantity?
Answer
Radius of gyration of a given body depends upon the choice of rotation axis. However, for a given axis of rotation, the radius of gyration of a body has a fixed value.
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Question 951 Mark
A planet revolves around a massive star in a highly elliptical orbit. Is its angular momentum conserved over the entire orbit?
Answer
Yes, since no external torque acts on the planets.
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Question 961 Mark
If a string of a rotating stone breaks, in which direction will the stone move?
Answer
The stone will move along the tangent at the point of breaking.
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Question 971 Mark
About which axis would a uniform cube have a minimum rotational inertia?
Answer
In a uniform cube, the mass is more concentrated about a diagonal.
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