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Question 11 Mark
What are the common types of secondary structure of proteins?
Answer
Secondary structure of protein: The secondary structure of protein refers to the shape in which a long polypeptide chain exist. They are found exist in two different types of structures viz. $\alpha$ - helix and β - pleated sheet structure. It arises due to the regular folding of the backbone of the polypeptide chain due to intermolecular hydrogen bonding between the carboxyl and amino group. In an $\alpha$ - helix, the peptide chain coils and the turns of the coil are held together by hydrogen bonds. In contrast to this, another type of secondary structure is possible in which the protein chains are stretched out and is known as β - structures.
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Question 21 Mark
What type of bonding helps in stabilising the $\alpha$ - helix structure of protins.
Answer
In the $\alpha$ - helix configuration, a polypeptide chain forms all possible hydrogen bonds by twisting into a right handed screw (helix) with -NH group of each amino acid residue hydrogen to the bonded $ \ \ \ \ \ \text{O}\\ \ \ \ \ \ ||\\ -\text{C}-$of an adjacent turn of the helix.
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Question 31 Mark
With reference to which classification has the statement, “ranitidine is an antacid” been given?
Answer
The statement refers to the classification according to pharmacological effect of the drug because any drug which will be used to counteract the effect of excess acid in the stomach will be called antacid. Antacids are the medicinal agents which decreases the excess level of hydrochloric acid in stomach.
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Question 41 Mark
Write IUPAC name of following and classify them into primary, secondary, tertiary amines:
$CH_3(CH_2)_2NH_2$
Answer
$CH_3(CH_2)_2NH_2$
1 - amino propane(primary)
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Question 51 Mark
What are the different types of RNA found in the cell?
Answer
  1. Messenger RNA (m-RNA)
  2. Ribosomal RNA (r-RNA)
  3. Transfer RNA (t-RNA)
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Question 61 Mark
How do you explain the amphoteric behaviour of amino acids?
Answer
In aqueous solution, the carboxyl group of an amino acid can lose a proton and the amino group can accept a proton to give a dipolar ion known as zwitter ion.
$ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ || \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ||\\\text{R}-\text{CH}-\text{C}-\text{O}-\text{H}\leftrightarrows\text{R}-\text{CH}-\text{C}-\text{O}^-\\ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ :\text{NH}_2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^+\text{NH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (\text{Zwitter ion})$
Therefore, in zwitter ionic form, the amino acid can act both as an acid and as a base. Thus, amino acids show amphoteric behaviour.
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Question 71 Mark
What do you understand by the term glycosidic linkage?
Answer

The ethereal or oxide linkage through which two monosaccharide units are joined together by the loss of a water molecule to form a molecule of disaccharide is called the glycosidic linkage. The glycosidic linkage in maltpse molecule is shown below:
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Question 81 Mark
The two strands in DNA are not identical but are complementary. Explain.
Answer
In the helical structure of DNA, the two strands are held together by hydrogen bonds between specific pairs of bases. Cytosine forms hydrogen bond with guanine, while adenine forms hydrogen bond with thymine. As a result, the two strands are complementary to each other.
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Question 91 Mark
What is the difference between a nucleoside and a nucleotide?
Answer

A nucleoside is formed by the attachment of a base $to^{I'}$ position of sugar.
Nucleoside = Sugar + Base

On the other hand, all the three basic components of nucleic acids (i.e., pentose sugar, phosphoric acid, and base) are present in a nucleotide. Nucleotide = Sugar + Base + Phosphoric acid
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Question 101 Mark
What are the expected products of hydrolysis of lactose?
Answer
Upon hydrolysis, lactose gives equivalent amounts of D (+) glucose and D (+) galactose.
$\text{C}_{12}\text{H}_{22}\text{O}_{11}+\text{H}_2\text{O}\xrightarrow[]{\text{Hydrolysis}}\text{C}_6\text{H}_{12}\text{O}_6\$+)-\text{Lactose} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{D}-(+)-\text{Glucose}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ +\text{C}_6\text{H}_{12}\text{O}_6\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{D}-(+)-\text{galactose}$
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Question 111 Mark
Define the following as related to proteins:
Peptide linkage.
Answer
Peptide linkage: In peptide linkage amide formed between -COOH groups of one molecule of an amino acid and $-NH_2$ group of another molecule of the amino acid by the elimination of a water molecules.
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Question 121 Mark
Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain.
Answer
The solubility of a solute in a given solvent follows the rule ‘Li ke dissolves like’.Glucose contains five and sucrose contains eight -OH groups. These -OH groups form H-bonds with water. As a result of this extensive intermoleeular H-bonding, glucose and sucrose are soluble in water.On the other hand, benzene and cyclohexane do not contain -OH bonds and hence do not form H-bonds with water. Moreover, they are non-polar molecules and hence do not dissolve in polar water molecules.
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Question 131 Mark
The melting points and solubility in water of amino acids are generally higher than that of the corresponding halo acids Explain.
Answer
The amino acids exist as zwitter ions, $H_3N^+ — CHR-COO-$. Due to this dipolar salt like character, they have strong dipole-dipole attractions. Therefore, their melting points are higher than corresponding haloacids which do not have salt like character.
Due to salt like character, amino acids intereact strongly with water. As a result, their solubility in water is higher than corresponding haloacids which do not have salt like character.
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Question 141 Mark
How do you explain the absence of aldehyde group in the pentaacetate of D-glucose?
Answer
D-glucose reacts with hydroxylamine $(NH_2OH)$ to form an oxime because of the presence of aldehydic (CHO) group or carbonyl carbon. This happens as the cyclic structure of glucose forms an open chain structure in an aqueous medium, which then reacts with $NH_2OH$ to give an oxime.
$\text{CHO} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}=\text{N}-\text{OH}\\ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \$\text{CHOH})_4\xrightarrow[]{\text{NH}_4\text{OH}} \ \ (\text{CHOH})_4\\ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_2\text{OH} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_2\text{OH}\\\text{Glucose} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Oxime}$
But pentaacetate of D-glucose does not react with $NH_2OH$. This is because pentaacetate does not form an open chain structure.
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Question 151 Mark
What products would be formed when a nucleotide from DNA containing thymine is hydrolysed?
Answer
The products obtained are 2-deoxy-D-ribose, Phosphoric acid and thymine.
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Question 161 Mark
Define the following as related to protein
Denaturation
Answer
In a biological system, a protein is found to have a unique 3-dimensional structure and a unique biological activity. In such a situation, the protein is called native protein. However, when the native protein is subjected to physical changes such as change in temperature or chemical changes such as change in pH, its H-bonds are disturbed. This disturbance unfolds the globules and uncoils the helix. As a result, the protein loses its biological activity. This loss of biological activity by the protein is called denaturation.
During denaturation, the secondary and the tertiary structures of the protein get destroyed, but the primary structure remains unaltered. One of the examples of denaturation of proteins is the coagulation of egg white when an egg is boiled.
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Question 171 Mark
What is the effect of denaturation on the structure of proteins?
Answer
Denaturation of proteins: Proteins are very sensitive to the action of heat, change of pH, presence of electrolytes and radiations (particularly of short wavelength). Whenever proteins are subjected to such changes in the surroundings, they undergo some structural changes leading to disruption of three dimensional structure. This causes permanent loss of activity to proteins. Disruption of the native conformation of protein, by changing its environment, resulting in loss of its biological activity, is known as denaturation of proteins.
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Question 181 Mark
What are monosaccharides?
Answer
Monosaccharides are carbohydrates Which cannot be hydrolysed to smaller molecules.Their general formula is $(CH_20)n$ Where n = 3 - 7 These are of two types: Those which contain an aldehyde group (-CHO) are called aldoses and those which contain a keto (C = O) group are called ketoses.
They are further classified as trioses, tetroses ,pentoses, hexoses and heptoses according as they contain 3, 4, 5, 6, and 7 carbon atoms respectively For example.
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Question 191 Mark
What are reducing sugars?
Answer
Carbohydrates which reduces Fehling's solution to red precipitate of $Cu_20$ or Tollen's reagent to metallic Ag are called reducing sugars.
All monosaccharides (both aldoses and ketoses) and disaccharides except sucrose are reducing sugars.
Thus, D - (+) - glucose, D-(-)-fructose, D - (+) - maltose and D - (+) - lactose are reducing sugars.
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Question 201 Mark
Why cannot vitamin C be stored in our body?
Answer
Vitamin C cannot be stored in our body because it is water soluble. As a result, it is readily excreted in the urine.
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Question 211 Mark
Write IUPAC name of the following compounds and classify them into primary, secondary and tertiary amines.
$C_6H_5NHCH_3$
Answer
N - Methylbenzamine or N - methylaniline(2° amine)
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Question 221 Mark
What are enzymes?
Answer
Enzymes are proteins that catalyze biological reaction. They are very specific in nature and catalyze only a particular reaction for a particular substrate. Enzymes are usually named after a particular. For example, the enzyme used to catalyses the hydrolysis of maltose in glucose is named as maltase.
$\text{C}_{12}\text{H}_{22}\text{O}_{11}\xrightarrow[]{\text{Maltase}}2\text{C}_6\text{H}_{12}\text{O}_6\\\text{maltose} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{glucose}$
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Question 231 Mark
Where does the water present in the egg go after boiling the egg?
Answer
Denaturation of proteins is a process in which physical and biological properties of protein without changing the chemical composition of protein. In an egg denaturation of protein is the coagulation of albumin present in the white of an egg. When egg is boiled in water, the globular proteins present in it changes to a rubber like insoluble mass which absorbs all water present in the egg.
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Question 241 Mark
Define the following as related to protein:
Primary structure.
Answer
Primary structure: The primary structure of protein refers to the specific sequence in which various amino acids are present in it, i.e., the sequence of linkages between amino acids in a polypeptide chain. The sequence in which amino acids are arranged is different in each protein. A change in the sequence creates a different protein.
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Question 281 Mark
What is meant by ‘reducing sugars’?
Answer
Carbohydrates which reduce Tollen’s reagent or Fehling solution are called reducing sugars which have free aldehydic group.
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Question 291 Mark
Write two main functions of carbohydrates in plants.
Answer
  1. Structural support.
  2. Storage molecules.
  3. Constituent of cell wall.
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Question 341 Mark
Arrange the following compounds in an increasing order of their solubility in water:
$C_6H_5NH_2, (C_2H_5)_2NH, C_2H_5NH_{2}.$
Answer
$C_6H_5NH_2 < (C_2H_5)_2NH < C_2H_5NH_{2}.$
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Question 351 Mark
Write the products obtained after hydrolysis of lactose.
Answer
Lactose is composed of $\beta-\text{D}$ galactose and $\beta-\text{D}$ glucose. Thus, on hydrolysis, it gives $\beta-\text{D}$ galactose and $\beta-\text{D}$ glucose.
$\text{C}_{12}\text{H}_{22}\text{O}_{11}\ \ \ +\ \ \ \text{H}_2\text{O}\ \ \ \xrightarrow{\ \ \ \ \ \ \ \ \ }\ \ \ \text{C}_6\text{H}_{12}\text{O}_6\ \ \ \ \ +\ \ \ \ \text{C}_6\text{H}_{12}\text{O}_6\\ \ \ \text{Lactose}\ \ \ \ \ \ \ \ \ \ \ \ \text{Water}\ \ \ \ \ \ \ \ \ \ \ \ \ \text{D}-\text{Glucose}\ \ \ \ \ \ \ \ \text{D}-\text{Galactose}$
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Question 371 Mark
What is the basic structural difference between glucose and fructose?
Answer
Both Glucose and Fructose are hexose sugars with six carbon atoms but, Glucose is an aldohexose and Fructose is ketohexose which means the functional group present in glucose is aldehyde and the functional group in fructose is ketone.
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Question 391 Mark
Write biological importance of nucleic acid.
Answer
  1. To transmit genetic material to their offsprings.
  2. Protein synthesis.
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Question 401 Mark
Some enzymes are named after the reaction, where they are used. What name is given to the class of enzymes which catalyse the oxidation of one substrate with simultaneous reduction of another substrate?
Answer
Oxidoreductase is class of enzymes which catalyse the oxidation of one substrate with simultaneous reduction of another substrate.
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Question 411 Mark
Name the molecule which provides energy for all the activities of a cell.
Answer
Adenosine triphosphate (ATP).
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Question 431 Mark
What are oligosaccharides?
Answer
Carbohydrates which on hydrolysis give 2-10 molecules of monosaccharides are called oligosaccharides. For example, sucrose, raffinose, stachyose, etc.
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Question 461 Mark
How do you explain the presence of five —OH groups in glucose molecule?
Answer
Glucose gives penta-acetyl derivative on acetylation with acetic anhydride.
$\text{CHO}| (\text{CHOH})_4|\text{CH}_2\text{OH}|\text{CH}_2\text{OH}\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{CHO}|(\text{CHOCOCH}_3)_4|\text{CH}_2\text{OH}_2\text{OCOCH}_3$
This confirms the presence of five -OH groups.
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Question 471 Mark
Name the sugar present in milk. How many monosaccharide units are present in it? What are such oligosaccharides called?
Answer
Lactose is present in milk. Two monosaccharide units (i.e., glucose and galactose) are present in it. Such oligosaccharides are called disaccharides.
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Question 481 Mark
Monosaccharides contain carbonyl group hence are classified, as aldose or ketose. The number of carbon atoms present in the monosaccharide molecule are also considered for classification. In which class of monosaccharide will you place fructose?
Answer
Monosaccharides contain carbonyl group. Hence, are classified as aldose or ketose.
When aldehyde group is present, the monosaccharides are known as aldose. When ketone group is present, the monosaccharides are known as ketose. Fructose has molecular formula $C_6H_{12}O_6$ containing six carbon and keto group and is classified as ketohexose.
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Question 491 Mark
The letters ‘D’ or ‘L’ before the name of a stereoisomer of a compound indicate the correlation of configuration of that particular stereoisomer. This refers to their relation with one of the isomers of glyceraldehyde. Predict whether the following compound has ‘D’ or ‘L’ configuration.
Answer
The letters ‘D’ or ‘L’ before the name of any compound indicate the relative configuration of a particular stereoisomer. This refers to their relation with a particular isomer of glyceraldehydes.
D’ before the name of glucose represents the configuration whereas ‘(+)’ represents dextrorotatory nature of the molecule. It may be remembered that ‘D’ and ‘L’ have no relation with the optical activity of the compound. For assigning the configuration of monosaccharides, it is the lowest asymmetric carbon atom which is compared. The given compound has L-configuration.
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Question 521 Mark
Write IUPAC names of following and classify them into primary, secondary, tertiary amines:
$CH_3NHCH(CH_3)_2$
Answer
$CH_3NHCH(CH_3)_2$
Methyl isopropyl amine (secondary)
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Question 531 Mark
Why is cellulose not digested in human body?
Answer
It is due to the fact that human beings do not have enzyme to digest cellulose.
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Question 571 Mark
Answer the following questions.
Name two fat storing tissues in human body.
Answer
Liver and adipose tissue.
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Question 601 Mark
Why does compound (A) given below not form an oxime?
Answer
Glucose pentaacetate (structure A) doesn’t have a free —OH group at C1 and so can’t be converted to the open chain form to give —CHO group and hence doesn’t form the oxime.
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Question 611 Mark
Why are carbohydrates generally optically active?
Answer
Carbohydrates have chiral or asymmetric carbon atom.
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Question 631 Mark
Amino acids can be classified as $\alpha-, \beta-, \delta-,$and so on depending upon the relative position of amino group with respect to carboxyl group. Which type of amino acids form polypetide chain in proteins?
Answer

$\alpha-$Amino acid,forms polypeptide chain in proteins.
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Question 651 Mark
Give an example each of essential and non-essential amino acids.
Answer
Valine is an essential amino acid whereas glycine is a non-essential amino acid.
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Question 681 Mark
How do enzymes help a substrate to be attacked by the reagent effectively?
Answer
Enzymes arehighly specific. They react with substrate molecule and form intermediate complex. They reduce the magnitude of activation energy.
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Question 691 Mark
Which moieties of nucleosides are involved in the formation of phosphodiester linkages present in dinucleotides? What does the word diester in the name of linkage indicate? Which acid is involved in the formation of this linkage?
Answer

Nucleosides are linked to phosphoric acid at 5′-position of sugar moiety to form a nucleotide. Further, nucleotides (two molecules) are joined together by phosphodiester linkage between 5′ and 3′ carbon atoms of pentose sugar to form dinucleotide. Phosphoric acid is involved in the formation of this linkage.
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Question 711 Mark
In nucleoside a base is attached at 1′ position of sugar moiety. Nucleotide is formed by linking of phosphoric acid unit to the sugar unit of nucleoside. At which position of sugar unit is the phosphoric acid linked in a nucleoside to give a nucleotide?
Answer
Phosphoric acid unit is linked preferably at 5′-position of sugar moiety of a nucleoside to give a nucleotide.
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Question 721 Mark
Aldopentoses named as ribose and 2-deoxyribose are found in nucleic acids. What is their relative configuration?
Answer
Configuration assigned is O. Thus, ribose is $\beta-$D-ribose Deoxyribose is $\beta-$D-2-deoxyribose.
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Question 731 Mark
$\alpha-$Helix is a secondary structure of proteins formed by twisting of polypeptide chain into right handed screw like structures. Which type of interactions are responsible for making the $\alpha-$helix structure stable?
Answer
In $\alpha-$helix, apolypeptide chain is stabilized by the formation of hydrogen bonds between NH— group of amino acids in one turn with the >C —O groups of amino acids belonging to adjacent turn.
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Question 741 Mark
Answer the following questions.
Name the protein and its shape present in oxygen carrier in human body.
Answer
Globular protein and its shape is spherical.
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Question 751 Mark
Answer the following questions.
Which of the following biomolecules is insoluble in water? Justify. Insulin, Haemoglobin, Keratin.
Answer
Keratin being a fibrous protein insoluble in water.
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Question 771 Mark
Structures of glycine and alanine are given below. Show the peptide linkage in glycylalanine. $\text{H}_{2}\text{N}-\text{CH}_{2}-\text{COOH} :\text{H}_2\text{N}-\text{CH}_2-\text{COOH}\\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Answer

The carboxyl group of glycine and amino group of alanine when combines together, they form glycylalanine through a peptide (-CO – NH) linkage.
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Question 781 Mark
Among B group vitamins $B_1, B_2, B_6$ and $B_{12} $ which vitamin can be stored in our body?
Answer
Vitamin $B_{12}.$
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Question 791 Mark
How do you explain the presence of all the six carbon atoms in glucose in a straight chain?
Answer
On prolonged heating with HI, glucose gives n-hexane.
$\text{Glucose}\ \xrightarrow{\ \ \ \ \ \ \ \ \ \ \text{HI} }\text{CH}_{3}-\text{CH}_{2}-\text{CH}_{2}-\text{CH}_{2}-\text{CH}_{3}$
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Question 801 Mark
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
$(CH3)_3CNH_2$
Answer
$(CH_3)_3CNH_2$
Tert-butylamine (primary amine)
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Question 811 Mark
How do you explain the presence of an aldehydic group in a glucose molecule?
Answer
Glucose gets oxidised to six carbon carboxylic acid (gluconic acid) on reaction with a mild oxidising agent like bromine water. This indicates that the carbonyl group is present as an aldehydic group.
$\ \text{CHO} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{COOH} \\ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \text{(CHOH)}_4 \xrightarrow{\text{Br}_2/\text{H}_2\text{O}}(\text{CHOH})_4\\ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \ \text{CH}_2\text{OH} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_2\text{OH} \\ \text{Glucose} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Glucose acid}$
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Question 821 Mark
Activation energy for the acid catalysed hydrolysis of sucrose is $6.22kJ\ mol^{–1},$ while the activation energy is only $2.15kJ\ mol^{–1}$ when hydrolysis is catalysed by the enzyme sucrase. Explain.
Answer
Enzymes are biocatalysts. They reduce the magnitude of activation energy by providing alternative path. In the hydrolysis of sucrose, the enzyme sucrase reduces the activation energy from $6.22kJ\ mol^{-1}$ to $2.15kJ\ mol^{-1}$. As a result, enzyme catalysed reactions occur at a much faster rate than the ordinary chemical reactions using conventional catalysts.
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Question 831 Mark
Write IUPAC name of the following compounds and classify them into primary, secondary and tertiary amines.
$(CH_3CH_2)_2NCH_3$
Answer
$(CH_3CH_2)_2 NCH_3$
N - Ethyl - N - methylethanamine $(3^\circ$ amine$)$
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Question 851 Mark
Under what conditions glucose is converted to gluconic and saccharic acid?
Answer
Glucose is converted to gluconic acid by $Br_2$ water and to saccharic acid by cone $HNO_3.$
$\ \text{CHO} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{COOH} \\ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \text{(CHOH)}_4 + \text{O} \xrightarrow{\text{Br}_2/\text{H}_2\text{O}}(\text{CHOH})_4\\ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \ \text{CH}_2\text{OH} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_2\text{OH} \\ \text{Glucose} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Gluconoc acid}$
$\ \text{CHO} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{COOH} \\ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \text{(CHOH)}_4 +3[ \text{O}] \xrightarrow{\text{Br}_2/\text{H}_2\text{O}}(\text{CHOH})_4\\ \ \ {|} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ {|} \\ \ \text{CH}_2\text{OH} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_2\text{OH} \\ \text{Glucose} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Saccharic acid}$
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Question 861 Mark
During curdling of milk, what happens to sugar present in it?
Answer
When milk is curdeled, its sugar get oxidize to form lactic acid.
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Question 891 Mark
What are glycosidic linkages? In which type of biomolecules are they present?
Answer
The two monosaccharides are joined together by an oxide linkage formed by the loss of a water molecule. Such a linkage between two monosaccharides is held together by a glycosidic linkage between $C_1$ of and $C_2$. Since the reducing groups of glucose and fructose are involved in glycosidic bond formation, between two monosaccharide units through oxygen atom is called glycosidic linkage.
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Question 901 Mark
Why must vitamin C be supplied regularly in diet?
Answer
Vitamin C are soluble in water. Water soluble vitamins must be supplied regularly in diet because they are readily excreted in urine and cannot be stored in our body.
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Question 931 Mark
What is the structural feature characterising reducing sugars?
Answer
The main structural feature of reducing sugars is the presence of an aldehyde group (-CHO) such as in glucose, mannose, galactose, etc. or a-ketol group (-CO- CH2OH) as present in fructose.
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Question 941 Mark
Name two of the different types of RNA molecules found in the cells of organisms.
Answer
Messenger RNA (mRNA) and transfer RNA (tRNA).
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Question 951 Mark
Among the amino acids phenylalanine, glutamine and alanine which one is an essential amino acid?
Answer
Phenylalanine is an essential amino acid.
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