Question 15 Marks
The odometer of a car reads $57321.0 \ km$ when the clock shows the time $08:30 \ AM$. What is the distance moved by the car, if at $08:50 \ AM$, the odometer reading has changed to $57336.0 \ km$? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Answer
View full question & answer→Initial reading of the odometer of the car $= 57321.0 \ km$
Final reading of the odometer of the car $= 57336.0 \ km$
Distance covered by the car
= Final reading of the odometer of the car − Initial reading of the odometer of the car
$= 57336.0 − 57321.0 = 15 km$
The given car starts at $8:30$ a.m. and stops at $8:50$ a.m.
Therefore, time taken by the car to cover the distance is $(8:50 − 8:30)$ min $= 20$ min
Distance covered by the car $= 15 km$
Time taken by the car $= 20$ min
$\text { Speed }=\frac{\text { Distanc covered }}{\text { Time taken }}=\frac{15}{20}=0.75 k \frac{ m }{ min }$
Again
$60 \min =1 h$
$20 \min =\frac{1}{60} \times 20=\frac{1}{3} h$
Time taken by the car $=\frac{1}{3} h$
$\text { Speed }=\frac{\text { Distance covered }}{\text { Time Taken }}=\frac{15}{\frac{1}{3}}=45 km / h$
Final reading of the odometer of the car $= 57336.0 \ km$
Distance covered by the car
= Final reading of the odometer of the car − Initial reading of the odometer of the car
$= 57336.0 − 57321.0 = 15 km$
The given car starts at $8:30$ a.m. and stops at $8:50$ a.m.
Therefore, time taken by the car to cover the distance is $(8:50 − 8:30)$ min $= 20$ min
Distance covered by the car $= 15 km$
Time taken by the car $= 20$ min
$\text { Speed }=\frac{\text { Distanc covered }}{\text { Time taken }}=\frac{15}{20}=0.75 k \frac{ m }{ min }$
Again
$60 \min =1 h$
$20 \min =\frac{1}{60} \times 20=\frac{1}{3} h$
Time taken by the car $=\frac{1}{3} h$
$\text { Speed }=\frac{\text { Distance covered }}{\text { Time Taken }}=\frac{15}{\frac{1}{3}}=45 km / h$





