MCQ
$0.01$ mole of iodoform $(CHI_3)$ reacts with $Ag$ to produce a gas whose volume at  $NTP$ is  ............. $\mathrm{mL}$

$2CHI_3 + 6Ag \to 6AgI(s) + C_2H_2(g)$

  • A
    $224$
  • $112$
  • C
    $336$
  • D
    None of these

Answer

Correct option: B.
$112$
b
mol of $\mathrm{C}_{2} \mathrm{H}_{2}=\frac{1}{2} \times \mathrm{mol}$ of $\mathrm{CHI}_{3}$

$=\frac{1}{2} \times 0.01=0.005$

$ \text { vol. at } \,\mathrm{N} \cdot \mathrm{T} \cdot \mathrm{P} =0.005 \times 22400 $

$=112\, \mathrm{ml}$

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