a
\(y=0.02(m) \sin \left[2 \pi\left(\frac{t}{0.04(s)}\right)-\frac{x}{0.50(m)}\right]\)

But \(y=a \sin (\omega t-k x)\)

\(\therefore \omega=\frac{2 \pi}{0.04} \Rightarrow v=\frac{1}{0.04}=25 H z\)

\(k=\frac{2 \pi}{0.50} \Rightarrow \lambda=0.5 \mathrm{m}\)

\(\therefore\) velocity, \(\mathrm{v}=v \lambda=25 \times 0.5 \mathrm{m} / \mathrm{s}=12.5 \mathrm{m} / \mathrm{s}\)

Velocity on a string is given by

\(v=\sqrt{\frac{T}{\mu}} \therefore T=\mathrm{v}^{2} \times \mu=(12.5)^{2} \times 0.04=6.25 \mathrm{N}\)