MCQ
$0.5\,L$ of gaseous hydrocarbon when burnt in excess of $O_2$ gave $3.5\,L$ of $CO_2$ and $4\,L$ of water vapours under same conditions. Molecular formula of the hydrocarbon will be
- A$C_4H_8$
- B$C_4H_{10}$
- ✓$C_7H_{16}$
- D$C_5H_{12}$
✓
Answer
Correct option: C.
$C_7H_{16}$
c
$\mathrm{n}_{\mathrm{C}}: \mathrm{n}_{\mathrm{H}}=3.5:(4 \times 2)$
$\mathrm{n}_{\mathrm{C}}: \mathrm{n}_{\mathrm{H}}=3.5:(4 \times 2)$
$=7: 16$
$\mathrm{MF}=\left(\mathrm{C}_{7} \mathrm{H}_{16}\right)_{\mathrm{x}}$
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