$ \mathrm{W}=\frac{\mathrm{M} \times \mathrm{M}_2 \times \mathrm{V}(\text { in } \mathrm{mL})}{1000}=\frac{0.75 \times 36.5 \times 25}{1000}$

$ =0.684 \mathrm{~g} \text { (Mass of } \mathrm{HCl}) $

$ \underset{36.5 \mathrm{~g}}{\mathrm{HCl}}+\underset{40 \mathrm{~g}}{\mathrm{NaOH}} \longrightarrow \mathrm{HCl}+\mathrm{NaOH} $

$36.5 \mathrm{~g} \mathrm{HCl}$ reacts with $\mathrm{NaOH}=40 \mathrm{~g}$

$0.684 \mathrm{~g} \mathrm{HCl} \text { reacts with } \mathrm{NaOH}=\frac{40}{36.5} \times 0.684=0.750 \mathrm{~g}$

Amount of $\mathrm{NaOH}$ left $=1 \mathrm{~g}-0.750 \mathrm{~g}=0.250 \mathrm{~g}=250 \mathrm{mg}$