MCQ
$1\, L$ aqueous solution of $H _{2} SO _{4}$ contains $0.02\, m$ mol $H _{2} SO _{4} .50\, \%$ of this solution is diluted with deionized water to give $1\, L$ solution $(A).$ In solution $(A)$, $0.01\, m \,mol$ of $H _{2} SO _{4}$ are added. Total $m$ $mols$ of $H _{2} SO _{4}$ in the final solution is $......\times 10^{3}\, m\, mols.$
  • A
    $3$
  • B
    $1$
  • C
    $2$
  • $0$

Answer

Correct option: D.
$0$
d
$n _{ H _{2} SO _{4}}$ in $Sol ^{ n } A =50 \%$ of original solution

$=0.01\, m \,mol$.

$n _{ H _{2} SO _{4}}$ in Final solution $=0.01+0.01$

$=0.02 \,m\,mol$

$=0.00002 \times 10^{3} \,m\,mol$

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