c
$K = \frac{P}{{\Delta V/V}}$ $\therefore \Delta V = \frac{{PV}}{K}$
$p = h\rho g = 200 \times {10^3} \times 10N/{m^2}$
$k = 22000\,atm = 22000 \times {10^5}N/{m^2}$
$V = 1{m^3}$
$\Delta V = \frac{{200 \times {{10}^3} \times 10 \times 1}}{{22000 \times {{10}^5}}} = 9.1 \times {10^{ - 4}}{m^3}$