$10\, kg$ block is placed as shown, if $F = 50$ newton find friction force ............ $N$
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$\mathrm{N}-\mathrm{mg}=0$
$F-f=0$
$f=F=50 N$
as $\mathrm{f}_{\mathrm{smar}}>\mathrm{F}$
$f_{\text {smax }}=\mu, N $
$= 0.6 \times 100$
$=60 \mathrm{N} $
$\therefore f=50\,N$
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