MCQ
$10\, mL$ of $2\,(M)\, NaOH$ solution is added to $200\, mL$ of $0.5\, (M)$ of $NaOH$ solution. What is the final concentration ?............. $\mathrm{M}$
- ✓$0.57$
- B$5.7$
- C$11.4$
- D$1.14$
${M_1}{V_1} + {M_2}{V_2} = M{V_{(total)}}$
$2 \times \frac{{10}}{{1000}} + 0.5 \times \frac{{200}}{{1000}} = M \times \frac{{210}}{{1000}}$
$120 = M \times 210$
$M = \frac{{120}}{{210}} = 0.57\,M$
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