$1.1= M \left[\frac{1}{1}+\frac{180}{1000}\right\rceil$
$\therefore 1.10= M \times 1.18$
$\therefore M =\frac{110}{118}=0.93 M$
$^{\mathrm{M}}\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}=267.46 \;\mathrm{g} / \mathrm{mol}$ $\mathrm{M}_{\mathrm{AgNO}_{3}}=169.87 \;\mathrm{g} / \mathrm{mol}$