\( = \,\,\,\left( {\frac{{10 - 5}}{{10 + 5}}} \right)10 + \left( {\frac{{2 \times 5}}{{10 + 5}}} \right)4\,\,\, = \left( {\frac{5}{{15}}} \right)10 + \left( {\frac{{10}}{{15}}} \right)4\,\,\, = \frac{{10}}{3} + \frac{8}{3}\,\,\, = \,\frac{{18}}{3}\,\,\, = \,6\,m/s\)
તેવી જ રીતે, \({\upsilon _2}'\, = \,\,\left( {\frac{{2{m_1}}}{{{m_1} + {m_2}}}} \right){\upsilon _1} + \,\,\left( {\frac{{{m_2} - {m_1}}}{{{m_1} + {m_2}}}} \right)\,{\upsilon _2}\) પરથી \(\upsilon _{\text{2}}^{\text{'}}{\text{ = 12 m/s}}\)
$\text { [ } g=10 \mathrm{~m} / \mathrm{s}^2]$લો.