10.0 ,~mL of 0.05 , M , KMnO_ 4 solution was consumed in a titrat… - Vidyadip

MCQ

$10.0 \,\mathrm{~mL}$ of $0.05\, \mathrm{M}\, \mathrm{KMnO}_{4}$ solution was consumed in a titration with $10.0\, \mathrm{~mL}$ of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is $.....\,\times 10^{-2} \,\mathrm{~g} / \mathrm{L}$ (Round off to the nearest integer)

A
$1782$
B
$2152$
C
$1203$
✓
$1575$

✓

Answer

Correct option: D.

$1575$

d
$\mathrm{n}_{\mathrm{eq}} \mathrm{KMnO}_{4}=\mathrm{n}_{\text {eq }}=\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}$

or, $\frac{10 \times 0.05}{1000} \times 5=\frac{10 \times \mathrm{M}}{1000} \times 2$

$\therefore$ Conc. of oxalic acid solution $=0.125 \,\mathrm{M}$

$=0.125 \times 126\, \mathrm{~g} / \mathrm{L}=15.75 \,\mathrm{~g} / \mathrm{L}$

$=1575 \times 10^{-2}\, \mathrm{~g} / \mathrm{L}$

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