Moles of solute \(=\frac{120}{60}=2\)
Mass of solution \(=1000+120=1120\, \mathrm{gm}\)
Density of solution \(=1.15\, \mathrm{g} / \mathrm{mL}\)
\(\therefore\) volume of solution \(=\frac{1120}{1.15}=973.9\, \mathrm{mL}=\frac{973.9}{1000}\) \(litre\) \(=0.9739\) \(litre\)
\(\therefore M=\frac{2}{0.9739}=2.05\)
$(Image)$
$x=$.. . . . . .(નજીક નો પૂર્ણાક)
[આપેલ : $273.15 \mathrm{~K}$ પર પાણીનો મોલલ ઠારણ બિંદુ અવનયન અયળાંક $1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ છે]