MCQ
$10\,g$ of $CaCO_3$ contains
- A$10\,moles$ of $CaCO_3$
- ✓$0.1\,g$ atom of $Ca$
- C$6\times 10^{23}$ atoms of $Ca$
- D$0.1$ of equivalent of $Ca$
✓
Answer
Correct option: B.
$0.1\,g$ atom of $Ca$
b
Mwt of $\mathrm{CaCO}_{3}=40+12+48=100$
Mwt of $\mathrm{CaCO}_{3}=40+12+48=100$
$ \text { Moles of } \mathrm{CaCO}_{3} \text { in } 10 \,\mathrm{g} =\frac{10}{100} $
$=0.1\, \mathrm{mol}=0.1 \,\mathrm{g} \,\text { atom }$
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