Question
11, 8, 5, 2, . . . In this A.P. which term is number – 151?
✓
Answer
By, given A.P. 11, 8, 5, 2, .
we know that
$a=11, t_1=8, t_2=5$
Thus, $d=t_2-t_1=5-8=-3$
Given: $t_n=-151$
Now, By using $\mathrm{n}^{\text {th }}$ term of an A.P. formula
$t_n=a+(n-1) d$
we can find value of " $n$ "
Thus, on substituting all the value in formula we get,
$-151=11+(n-1) \times(-3)$
$\Rightarrow-151-11=(n-1) \times(-3)$
$\Rightarrow-162=(n-1) \times(-3)$
$\Rightarrow n-1=\frac{-162}{-3}=54$
$\Rightarrow n=54+1=55$
we know that
$a=11, t_1=8, t_2=5$
Thus, $d=t_2-t_1=5-8=-3$
Given: $t_n=-151$
Now, By using $\mathrm{n}^{\text {th }}$ term of an A.P. formula
$t_n=a+(n-1) d$
we can find value of " $n$ "
Thus, on substituting all the value in formula we get,
$-151=11+(n-1) \times(-3)$
$\Rightarrow-151-11=(n-1) \times(-3)$
$\Rightarrow-162=(n-1) \times(-3)$
$\Rightarrow n-1=\frac{-162}{-3}=54$
$\Rightarrow n=54+1=55$
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