$110\; J$ of heat is added to a gaseous system, whose internal energy change is $40\; J$, then the amount of external work done is ........ $J$
AIPMT 1993, Easy
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$\Delta Q = \Delta U + \Delta W$ $\Rightarrow$ $\Delta W = \Delta Q - \Delta U = 100 - 40 = 70J$
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