Figure shows, the adiabatic curve on a $\log T$ and log $V$ scale performed on ideal gas. The gas is ............
Medium
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(a)
$T V^{\gamma-1}=K$
$\log T+(\gamma-1) \log V=0$
$\log T=-(\gamma-1) \log V$
$y=-(\gamma-1) x$
$\frac{y}{x}=-(\gamma-1)=\text { slope }=\frac{2-4}{4-1}$
$\Rightarrow-(\gamma-1)=-\frac{2}{3}$
$\gamma=\frac{5}{3}$
$\therefore \text { Monoatomic.}$
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