\(\Rightarrow 110=(220)(I)\)

\(\Rightarrow I=0.5 \mathrm{~A}\)

\(\text { Now, } I=\frac{\mathrm{n} \cdot \mathrm{e}}{\mathrm{t}}\)

\(\Rightarrow 0.5=\left(\frac{\mathrm{n}}{\mathrm{t}}\right)\left(1.6 \times 10^{-19}\right)\)

\(\Rightarrow \frac{\mathrm{n}}{\mathrm{t}}=\frac{0.5}{1.6 \times 10^{-19}}\)

\(\Rightarrow \frac{\mathrm{n}}{\mathrm{t}}=31.25 \times 10^{17}\)