MCQ
$1.12\, ml$ of a gas is produced at $STP$ by the action of $4.12\, mg$ of alcohol, with methyl magnesium iodide. The molecular mass of alcohol is
- A$16$
- B$41.2$
- ✓$82.4$
- D$156$
✓
Answer
Correct option: C.
$82.4$
c
(c) $1.12 \,mL$ is obtained from $4.12\, mg$
(c) $1.12 \,mL$ is obtained from $4.12\, mg$
$\therefore$ $22400\, mL$ will be obtained from
$\frac{{4.12}}{{1.12}} \times 22400\,mg = 84.2\,g$
$\underset{1\,mol.}{\mathop{ROH}}\,+C{{H}_{3}}MgI\to \underset{1\,mol=22400\,cc}{\mathop{C{{H}_{4}}+Mg<_{I}^{OR}}}\,$
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