\(\,\therefore \,\,\,\frac{{{n_{NaHC{O_3}}}}}{{{n_{C{O_2}}}}}\,\, = \,\,\frac{2}{1}\)
\(\therefore \,\,{n_{NaHC{O_3}}}\, = \,2{n_{C{O_2}}}\,\, = \,\,2\, \times \,\frac{{112}}{{22400}}\, = \,0.01\,mole\)
\(\therefore \,\,{W_{NaHC{O_3}}}\, = \,0.01\, \times \,84\,\, = \,\,0.84\,g\,\,;\,\)
\({W_{N{a_2}C{O_3}}}\,\, = \,\,1.00\, - \,0.84\, = \,0.16g\,\)
\(\therefore \,\,\,\% \,N{a_2}C{O_3}\, = \,16\)