$K _{ p }=\frac{ P ^2 NO _2}{ P _{ S _2 O _4}}=\frac{(0.3)^2}{0.7}=\frac{0.09}{0.7}=\frac{9}{70}$
હવે,કુલ દબાણ $=9$ હોય ત્યારે
ધારો કે $P _{ NO _2}= x \therefore P _{ N _2 O _4}=9- x$
$K_P=\frac{9}{70}=\frac{x^2}{9-x}$
$\therefore 81-9 x=x^2$
$\therefore 70 x^2+9 x-81=0$
$\therefore x=1.01$
$\therefore P_{ N _2 O_4}=9-x=7.99$
${N_2}(g) + {O_2}(g) \rightleftharpoons 2NO(g)$
${N_2}{O_4}(g) \rightleftharpoons 2N{O_2}(g)$
${N_2}(g) + 3{H_2}(g) \rightleftharpoons 2N{H_3}(g)$
$2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ માટે સંતુલન અચળાંક ......... થશે.