MCQ
$2$ $mol$ of ${N_2}$ is mixed with $6$ $mol$ of ${H_2}$ in a closed vessel of one litre capacity. If $50\%$ of ${N_2}$ is converted into $N{H_3}$ at equilibrium, the value of ${K_c}$ for the reaction ${N_{2(g)}} + 3{H_{2(g)}}$ $\rightleftharpoons$ $2N{H_{3(g)}}$ is
  • $4/27$
  • B
    $27/4$
  • C
    $1/27$
  • D
    $24$

Answer

Correct option: A.
$4/27$
(a) $\mathop {\mathop {{N_2}}\limits^a }\limits_{(a - x)} + \mathop {\mathop {3{H_2}}\limits^b }\limits_{(b - 3x)} $ $ \rightleftharpoons $ $\mathop {\mathop {2N{H_3}}\limits^0 }\limits_{(2x)} $

$50\%$ Dissociation of ${N_2}$ take place so,

At equilibrium $\frac{{2 \times 50}}{{100}} = 1$; value of $x = 1$

${K_c} = \frac{{{{[2]}^2}}}{{[1]\,{{[3]}^3}}} = \frac{4}{{27}}$ so, ${K_c} = \frac{4}{{27}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free