MCQ
The percentage of $Se$ in peroxidase anhydrous enzyme is $0.5\%$ by weight (atomic weight $=78.4$). Then minimum molecular weight of peroxidase anhydrous enzyme is
- ✓$1.568 \times {10^4}$
- B$1.568 \times {10^3}$
- C$15.68$
- D$3.136 \times {10^4}$
✓
Answer
Correct option: A.
$1.568 \times {10^4}$
a
(a) $0.5\,gm$ $Se$ $ \to $ $100\,gm $ peroxidase anhydrous enzyme $78.4\,gm$ $Se$ $ \to \frac{{100 \times78.4}}{{0.5}} = 1.568 \times {10^4}$
(a) $0.5\,gm$ $Se$ $ \to $ $100\,gm $ peroxidase anhydrous enzyme $78.4\,gm$ $Se$ $ \to \frac{{100 \times78.4}}{{0.5}} = 1.568 \times {10^4}$
Minimum m.w. $ \to $molecule at least contain one selenium.
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