MCQ
$2$ moles of $PC{l_5}$ were heated in a closed vessel of $2$ litre capacity. At equilibrium, $40\%$ of $PC{l_5}$ is dissociated into $PC{l_3}$ and $C{l_2}$. The value of equilibrium constant is
  • $0.266$
  • B
    $0.53$
  • C
    $2.66$
  • D
    $5.3$

Answer

Correct option: A.
$0.266$
(a) $\mathop {PC{l_5}}\limits_2 $ $ \rightleftharpoons $ $\mathop {PC{l_3}}\limits_0 + \mathop {C{l_2}}\limits_0 $

$\frac{{2 \times 60}}{{100}}$    $\frac{{2 \times 40}}{{100}}$    $\frac{{2 \times 40}}{{100}}$

Volume of container $= 2$ litre.

${K_c} = \frac{{\frac{{2 \times 40}}{{100 \times 2}} \times \frac{{2 \times 40}}{{100 \times 2}}}}{{\frac{{2 \times 60}}{{100 \times 2}}}} = 0.266$.

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