(આપેલ : $K _{ b }\left( NH _4 OH \right)=1 \times 10^{-5}, \log 2=0.30, \log 3=0.48, \log 5=0.69, \log 7=0.84, \log 11=$ $1.04)$
$\left[ NH _{4}^{+}\right]=\frac{2\,m\,mole }{60\,ml }=\frac{1}{30}\,M$
$pH =\frac{ pK _{ w }- pK _{ b }-\log C }{2}=\frac{14-5+1.48}{2}=5.24$