\(\Lambda_{ m } \propto \frac{1}{ M }\)
\(\frac{\Lambda_{ m _{1}}}{\Lambda_{ m _{2}}}=\frac{ M _{2}}{ M _{1}}=\frac{\frac{20}{80}}{\frac{10}{20}}=\frac{1}{4} \times \frac{2}{1}=\frac{1}{2}\)
\(\Lambda_{ m _{2}}=2 \Lambda_{ m _{1}}\)
$[\Lambda_{\mathrm{H}^{+}}^{\circ}=350 \,\mathrm{~S}\, \mathrm{~cm}^{2}\, \mathrm{~mol}^{-1},\Lambda_{\mathrm{CH}_{3} \mathrm{COO}^{-}}^{\circ}=50\, \mathrm{~S}\, \mathrm{~cm}^{2}\, \mathrm{~mol}^{-1}]$
$Mn^{2+} +2e- \rightarrow Mn;\, E^o = -1.18\,V$
$2(Mn^{3+} +e^- \rightarrow Mn^{2+} )\,;\,E^o=+1.51\,V$
તો $3Mn^{2+} \rightarrow Mn+ 2Mn^{3+}$ માટે $E^o$ કેટલો થશે ?
$A.$ $Cl _{2} / Cl^{-}$ $B.$ $I _{2} / I^{-}$ $C.$ $Ag ^{+} / Ag$ $D.$ $Na ^{+} / Na$ $E.$ $Li ^{+} / Li$
નીચે આપેલામાંથી સાચો વિકલ્પ પસંદ કરો.