- A$0.75$ and $1$
- B$0.8$ and $1$
- C$1$ and $0.8$
- ✓$1$ and $1$
Moles of solute $=\frac{25 \mathrm{g}}{250 \mathrm{g} / \mathrm{mol}}=0.1 \mathrm{mol}$
Density of water $=1 \mathrm{g} / \mathrm{ml}$
Mass of solvent (water) $=100\; ml \times 1 \frac{\mathrm{g}}{\mathrm{ml}}=100 \mathrm{g}=0.1 \mathrm{kg}$
Molality $=\frac{\text { Moles of solute }}{\text { Mass of solvent (in kg) }}$
Molality $=\frac{0.1 \mathrm{mol}}{0.1 \mathrm{kg}}=1 \mathrm{m}$
Molality of solution is $1 \mathrm{m}$
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$H_2C = CH - CH_2 - I \xrightarrow[CC{{l}_{4}}]{HI(excess)}$
$S{O_2}C{l_2}(g) \rightleftharpoons S{O_2}(g) + C{l_2}(g)$
$CO(g) + C{l_2}(g) \rightleftharpoons COC{l_2}(g)$
On adding more $SO_2$ at equilibrium what will happen ?

| List$-I$ | List$-II$ |
| $A$ Coke | $I$ Carbon atoms are $sp ^3$ hybridised |
| $B$ Diamond | $II$ Used as a dry lubricant |
| $C$ Fullerene | $III$ Used as a reducing agent |
| $D$ Graphite | $IV$ Cage like molecules |
Choose the correct answer from the options given below :
${\left[ {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,||} \\
{C{H_2} = N = O}
\end{array}} \right]^\Theta }$