\(=\frac{1000 \times W}{M_m \times V}=\frac{\text { 1000 } \times 2.65}{106 \times 250}=\frac{10.6}{106}\)
\(=0.1\)
\(\begin{array}{ll} M _1=0.1 & M _2=(?) \\ V _1=10 & V _2=0.1 \, L =100\, mL \end{array}\)
\(\begin{aligned} & M _1 V _1= M _2 V _2 \\ \therefore & M _2=\frac{ M _1 V _1}{ V _2}=\frac{0.1 \times 10}{100}=0.01\,M \end{aligned}\)
(આપેલ : $Mg$ નો પરમાણ્વીય દળ $24\, g\, mol ^{-1} ; N _{ A }=6.02 \times 10^{23}\, mol ^{-1}$ )
($Ba$ નું પરમાણ્વીય દળ $=\,137$)
$Na _2 O + H _2 O \rightarrow 2 X$
$Cl _2 O _7+ H _2 O \rightarrow 2 Y$