$25\,^o C$ એ આપેલ માહિતી પરથી

$Ag+ I^- \rightarrow AgI +e^-,$ $E^o = 0.152\, V$

$Ag \rightarrow Ag^+ +e^-,$ $E^o =-0.800\, V$

$AgI$ માટે log $K_{sp}$નું મૂલ્ય શું થશે ? $(2. 303\, RT/F= 0. 059\, V)$

Question

$25\,^o C$ એ આપેલ માહિતી પરથી

$Ag+ I^- \rightarrow AgI +e^-,$ $E^o = 0.152\, V$

$Ag \rightarrow Ag^+ +e^-,$ $E^o =-0.800\, V$

$AgI$ માટે log $K_{sp}$નું મૂલ્ય શું થશે ? $(2. 303\, RT/F= 0. 059\, V)$

AIEEE 2006, Diffcult

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Solution

b
$(i)$ $A g \rightarrow A g^{+}+e$

$E^{\circ}=-0.800\, V$

$(ii)$ $A g+\mathrm{I}^{-} \rightarrow A g \mathrm{I}+e$

$E^{\circ}=0.152\, V$

From ( $i$ ) and $(ii)$ we have,

$A g \mathrm{I} \rightarrow A g^{+}+\mathrm{I}$

$E^{\circ}=-0.952\, V$

$E_{c e l l}^{\circ}=\frac{0.059}{n} \log K$

$\therefore-0.952=\frac{0.059}{1} \log \left[A g^{+}\right]\left[\mathrm{I}^{\mathrm{I}}\right]$

[as $k=\left[A g^{+}\right]\left[\mathrm{I}^{-}\right]$

$\quad-\frac{0.952}{0.059}=\log K_{s p}$

$\quad-16.13=\log K_{s p}$

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