$E_{c e l l}=E_{c c l l}^{\circ}-\frac{0.059}{2} \log \left(\frac{\left[Z n^{2+}\right]}{\left[C u^{2+}\right]}\right)$
$\quad 0-1.1-\frac{0.059}{2} \log \left(\frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cu}^{2+}\right]}\right)$
$\log \left(\frac{\left[Z n^{2+}\right]}{\left[C u^{2}\right]}\right)=\frac{2 \times 1.1}{0.059}=37.3$
$\therefore \quad\left(\frac{\left[Z n^{2+}\right]}{\left[C u^{2+}\right]}\right)=10^{37.3}$
$2Fe(s)\, + \,{O_2}\,(g)\, + \,4{H^ + }(aq)\, \to \,2F{e^{2 + }}(aq) + 2{H_2}O(l)\,;$ $E^o =1.67\,V$
$[Fe^{2+}] = 10^{-3}\, M$, $p(O_2) = 0.1\,atm$ અને $pH = 3$, $25\,^oC$ તાપમાને સેલ પોટેન્શિયલ .............. $\mathrm{V}$
$Zn^{2+} + 2e^-$ $\longrightarrow$ $Zn (s) ; E^o = -0.76\,V$
$Ca^{2+} + 2e^-$ $\longrightarrow$ $Ca (s) ; E^o = -2.87\,V$
$Mg^{2+} + 2e^-$ $\longrightarrow$ $Mg (s) ; E^o = -2.36\,V$
$Ni^{2+} + 2e^-$ $\longrightarrow$ $Ni (s) ; E^o = -0.25\,V$
ધાતુઓની રિડક્શનકર્તા ઉર્જાનો ચઢતો ક્રમ કયો થશે?